The only option that fits is E, because:
f(10)=4×10+10=50
If there are 30 days and 15 are sunny then 50% are sunny.
He does not have enough material
<h3>How to determine if he has
enough material?</h3>
The given parameters are
Area = 75 square feet
Perimeter of material = 32 feet
Calculate the side length using
Length = Perimeter/4
So, we have
Length = 32/4
Evaluate
Length = 8
The area is
Area = 8^2
Evaluate
Area = 64
64 is less than 75
Hence, he does not have enough material
Read more about perimeters at
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Athena purchased a chain for $5 and sold it for $ 15, her profit for each chain is $15-$5. So for 2 chains, her net profit = 2*(15-5)
She also purchased bracelets for $8 and sold them for $9, her profit for each chain is $9-$8 . So for three 3 bracelets, her net profit = 3*(9-8)
Net profit from chains = 2*(15-5) or 2*15 - 2*5 (distributive property)
Net profit from chains = 2*10 or 10*2 (Commutative property)
Net profit from chains= $20
Net profit from bracelets = 3*(9-8) or 3*9 -3*8 (distributive property)
Net profit from bracelets = 3*1 or 1*3 (Commutative property)
Net profit from bracelets = $3
Answer:
(a) 512 dimes
(b)
(c) 9.22337 x 10¹⁸ dimes
(d) 9.22337 x 10¹² km
(e) roughly 61,489.13 times longer than the distance from the earth to the sun.
Step-by-step explanation:
b. Starting with 1 dime in the first square, if the number of dimes per each square is the double of the previous square, the general equation for the number of dimes in each square 'n' can be found by:
a. On the 10th square:
c. On the 64th square:
d. If a dime is 1 mm thick, the 64th pile will be:
e. The ratio between the height of the last pile (h) to the distance from the earth to the sun is:
The height of the last pile is roughly 61,489.13 times longer than the distance from the earth to the sun.
