17/7=3x + 2(5) / 3x

The stock's value dropped from $38.50 to $34.00.What negative number shows the change in value?

schepotkina [342]

$-4.50 change in value

5 0

3 years ago

-4w+18w+2=10-6w <br><br> What is w?

kiruha [24]

Answer:

w = .5

Step-by-step explanation:

-4w + 18w+2=10 -6w

14w + 2 -2 = 10 -2 -6w

14w + 2w = 8 - 2w + 2w

16w = 8

16w/16 = 8/16

w = .5

8 0

3 years ago

Read 2 more answers

For every 20 penguins at the North Pole there are 9 polar bears. If you encountered 27 polar bears, how many penguins would you

cluponka [151]

Answer:

60 penguins

Step-by-step explanation:

We need to find out how many times 9, the number of polar bears for every 20 penguins, was multiplied by, so that we can multiply 20 penguins by the same amount.

27/9 = 3

20*3 = 60

5 0

3 years ago

Read 2 more answers

Please, can someone help?

LekaFEV [45]

The area of that figure is 2453.25 square feet

First, you would need to find the area of the rectangle

(L)(W)
(70)(30)
2100

Then since it is only a semi circle, the formula is pi*r^2/2

You find the area of a full circle first

(3.14)(15^2)
(3.14)(225)
706.5

Then you divide that by 2 since it’s only half a circle

706.5/2 = 353.25

Finally you add that by the area of the rectangle

2100 + 353.25 = 2453.25 square feet

3 0

3 years ago

A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far

ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

$\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}$ (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is: