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3 years ago

Please help!!!

Mathematics

1 answer:

Effectus [21]3 years ago

6 0

Answer:

a + b + c + d + e = 180.

Step-by-step explanation:

We can prove that a = angle CBA (vertically opposite angles are equal).

Now, since lines DE and CA are parallel, then it follows that c = angle ACE (alternate angles are equal). Similarly, b = angle CAD.

But notice that what we've just done is found the angles of the triangle CBA.

So the sum of the angles (a + b + c + d + e) is the sum of the angles of a triangle.

We then conclude that a + b + c + d + e = 180 degrees.

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In △MNO, m = 20, n = 14, and m∠M = 51°. How many distinct triangles can be formed given these measurements?

Gnom [1K]

Answer:

There is only one distinct triangle possible, with m∠N ≈ 33°. i hope this helps :)

Step-by-step explanation:

In △MNO, m = 20, n = 14, and m∠M = 51°. How many distinct triangles can be formed given these measurements?

There are no triangles possible.

There is only one distinct triangle possible, with m∠N ≈ 33°.

There is only one distinct triangle possible, with m∠N ≈ 147°.

There are two distinct triangles possible, with m∠N ≈ 33° or m∠N ≈ 147°.

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3 years ago

Read 2 more answers

Simplify x+2/x^2+2x-3 divide by x+2/x^2-x

ira [324]

$\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}$

If $x\neq-2$ , then we can immediately cancel the factors of $x+2$ :

$\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}$

Factorize the numerator and denominator:

$x^2-x=x(x-1)$

$x^2+2x-3=(x+3)(x-1)$

Next, if $x\neq1$ , then

$\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}$

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3 years ago

You go to "Ice Cream Palace" for dessert one day. You can get vanilla, chocolate, or twist ice cream. You have a choice of rainb

Kitty [74]

Answer:

54 combinations.

Explanation:

3x3x2x3= 54

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3 years ago

Jan bought 4 pounds of candy for $12.25. what was the average cost per pound to the nearest cent?

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It would be about $3.00

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2 years ago

Could someone pls send me an example of using the substitution method in algebra?

Elden [556K]

Answer:

in this method a variable is expressed in terms of another variable from one equation and it is substituted in remaining equation.

Step-by-step explanation:

solve:x+2y=9 and 3x-y=13.

x+ 2y=9…be the first equation

3x-y=13…be the second equation

from first equation

x=9-2y…be the third equation substituting value of x from third equation in second equation, we get

3(9-2y)-y=13

or, 27-6y-y=13

or, y=2

now,

substituting value of y in third equation, we get,

x=9-2×2

=9-4

the required value of x and y are 5&2

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4 years ago