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Inessa05 [86]
3 years ago
7

You run at a pace of 8.5 minutes per mile in a 26.2 mile marathon. How many minutes will it take finish?

Mathematics
1 answer:
algol [13]3 years ago
4 0
8.5 minutes per mile is equivalent to 

17 minutes
----------------
  2 miles

and the reciprocal of that is


2 miles
-----------
17 min

Now multiply 26.2 miles by 

17 min                                   (17 min)* (26.2 mi)
------------ ,    obtaining         ---------------------------
 2 miles                                           2 mi

This simplifies to (17)(26.2)/2 minutes = 222.7 minutes, 

or

222.7 minutes        1 hr
-------------------- * ------------ = 3.7 hours
          1                  60 min
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Thomas rents a car for his vaccation the milliage included with the 54 miles forer every mile he drives over 54 miles he needs t
Sauron [17]

Answer:

$27

Step-by-step explanation:

Thomas rents a car for his vacation. The mileage include with the rental is 54 miles. For every mile he drives over 54 miles, he needs to pay $1 4/5. If he drives 69 miles, how much extra does he need to pay?

Total mileage included with the rental = 54 miles

Additional cost per mile after 54 miles = $1 4/5

Total miles Thomas drives = 69 miles

Extra miles Thomas drives = 69 miles - 54 miles

= 15 miles

how much extra does he need to pay?

Extra cost Thomas needs to pay = Additional cost per mile after 54 miles * Extra miles Thomas drives

= $1 4/5 * 15 miles

= 9/5 * 15

= (9 * 15) / 5

= 135/5

= 27

Extra cost Thomas needs to pay = $27

4 0
3 years ago
The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.954 grams and a standard devia
olga_2 [115]

Let <em>X</em> be the random variable representing the amount (in grams) of nicotine contained in a randomly chosen cigarette.

P(<em>X</em> ≤ 0.37) = P((<em>X</em> - 0.954)/0.292 ≤ (0.37 - 0.954)/0.292) = P(<em>Z</em> ≤ -2)

where <em>Z</em> follows the standard normal distribution with mean 0 and standard deviation 1. (We just transform <em>X</em> to <em>Z</em> using the rule <em>Z</em> = (<em>X</em> - mean(<em>X</em>))/sd(<em>X</em>).)

Given the required precision for this probability, you should consult a calculator or appropriate <em>z</em>-score table. You would find that

P(<em>Z</em> ≤ -2) ≈ 0.0228

You can also estimate this probabilty using the empirical or 68-95-99.7 rule, which says that approximately 95% of any normal distribution lies within 2 standard deviations of the mean. This is to say,

P(-2 ≤ <em>Z</em> ≤ 2) ≈ 0.95

which means

P(<em>Z</em> ≤ -2 or <em>Z</em> ≥ 2) ≈ 1 - 0.95 = 0.05

The normal distribution is symmetric, so this means

P(<em>Z</em> ≤ -2) ≈ 1/2 × 0.05 = 0.025

which is indeed pretty close to what we found earlier.

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Answer:

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Step-by-step explanation:

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