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Mandarinka [93]
4 years ago
11

____________improves the understandability of a website, by maintaining similar design elements throughout.

Computers and Technology
1 answer:
lora16 [44]4 years ago
4 0

Simple and easy user interface design can help the users understand what they can do on the website, without confusion when they are loading on the website.

Best practice on the users experiences can help the users to visit the website easily and get what they want as fast as possible. It is the way to improve a website understandability.

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4. Select the correct answer.
3241004551 [841]

Answer: B.  PDF

Explanation:

Portable Document Format (PDF) is such an important document that it is considered the international standard for information and document exchange. It is used for letters, resumes and even electronic contracts.

PDF was developed by Adobe to make it independent of the device or application it is being viewed on and combines layers of information into one layer thereby making it a flat document.

7 0
3 years ago
I need to create a method named "root positive". which will either print the square root of the number passed to it or if the nu
rjkz [21]

Answer:

Explanation:

The following code is written in Java. It is a method that calculates the square root of a number as requested. The method first checks with an IF statement if the parameter value is a positive number and then calculates the square root and prints it to the screen. Otherwise, it prints Number must not be negative. A test case has been provided in the main method and the output can be seen in the attached image below.

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.print("Enter a number of type double to calculate square root:");

       double num = in.nextDouble();

       rootPositive(num);

   }

   public static void rootPositive(double num) {

       if (num > 0) {

           System.out.println(Math.sqrt(num));

       } else {

           System.out.println("Number must not be negative.");

       }

   }

}

5 0
3 years ago
What was one important academic skill the blogger learned?
denis23 [38]

An academic skill that the blogger learned, was to review the graded tests and quizzes to see which concepts he missed out on so that in the future he would be well prepared for it. Reviewing and comparing the tests and quizzes would give him an idea on which topics he needs to study.

Other than the academic skill, the blogger also learned that a person should never give up and he keeps on learning throughout his entire life, and that all of the improvements that the blogger made did not come all at once.

4 0
4 years ago
Linda is a core member of a project. She estimates the cost of the project, creates project requirements, and notes risks. What
lord [1]

Explanation:

no linda is the core member not rhe project

4 0
3 years ago
Write a python program to read four numbers (representing the four octets of an IP) and print the next five IP addresses. Be sur
sdas [7]

Answer:

first_octet = int(input("Enter the first octet: "))

second_octet = int(input("Enter the second octet: "))

third_octet = int(input("Enter the third octet: "))

forth_octet = int(input("Enter the forth octet: "))

octet_start = forth_octet + 1

octet_end = forth_octet + 6

if (1 <= first_octet <= 255) and (0 <= second_octet <= 255) and (0 <= third_octet <= 255) and (0 <= forth_octet <= 255):

   for ip in range(octet_start, octet_end):

       forth_octet = forth_octet + 1

       if forth_octet > 255:

           forth_octet = (forth_octet % 255) - 1

           third_octet = third_octet + 1

           if third_octet > 255:

               third_octet = (third_octet % 255) - 1

               second_octet = second_octet + 1

               if second_octet > 255:

                   second_octet = (second_octet % 255) - 1

                   first_octet = first_octet + 1

                   if first_octet > 255:

                       print("No more available IP!")

                       break

       print(str(first_octet) + "." + str(second_octet) + "." + str(third_octet) + "." + str(forth_octet))

else:

   print("Invalid input!")

Explanation:

- Ask the user for the octets

- Initialize the start and end points of the loop, since we will be printing next 5 IP range is set accordingly

- Check if the octets meet the restrictions

- Inside the loop, increase the forth octet by 1 on each iteration

- Check if octets reach the limit - 255, if they are greater than 255, calculate the mod and subtract 1. Then increase the previous octet by 1.

For example, if the input is: 1. 1. 20. 255, next ones will be:

1. 1. 21. 0

1. 1. 21. 1

1. 1. 21. 2

1. 1. 21. 3

1. 1. 21. 4

There is an exception for the first octet, if it reaches 255 and others also reach 255, this means there are no IP available.

- Print the result

8 0
3 years ago
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