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Temka [501]
3 years ago
12

Solve the following proportion for u u/5=8/3 round answer to nearest tenth

Mathematics
1 answer:
rjkz [21]3 years ago
4 0

Answer:

Step-by-step explanation:

u/5=8/3

multiply by : 5

u = 40/3

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????????????????????
Annette [7]

Answer:

A.

Step-by-step explanation:

8 0
3 years ago
Please help. Will give brain!!
charle [14.2K]

Answer: I believe it's 5 I am not sure

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
You have 6L feet of fence to make a rectangular vegetable garden alongside the wall of your house, where L is a positive constan
nika2105 [10]

Answer:

A(max) = (9/2)*L² ft²

Dimensions:

x = 3*L feet

y  = (3/2)*L   ft

Step-by-step explanation:

Let call  "x"  and  " y " sides of the rectangle. The side x is parallel to the wall of the house then

Area of the rectangle is  

A(r) = x*y

And total length of fence available is 6*L f , and we will use the wall as one x side then, perimeter of the rectangle which is 2x  +  2y   becomes x + 2*y

Then

6*L  =  x + 2* y    ⇒ y  = ( 6*L - x ) /2

And the area as function of x is

A(x)  =   x* ( 6*L - x )/2

A(x)  = ( 6*L*x  - x² ) /2

Taking derivatives on both sides of the equation we get:

A´(x)  =  1/2 ( 6*L - 2*x )

A´(x)  =  0      ⇒      1/2(  6*L  - 2*x ) = 0

6*L - 2*x  = 0

-2*x  = - 6*L

x  =  3*L feet

And

y  = ( 6*L - x ) /2   ⇒  y  = ( 6*L - 3*L )/ 2

y = ( 3/2)*L feet

And area maximum is:

A(max)  =  3*L * 3/2*L

A(max)  = (9/2)*L² f²

4 0
3 years ago
Read 2 more answers
What is the amplitude of sin ?
sp2606 [1]

You haven't provided a graph or equation so I will tell the simplified meaning of amplitude instead.

Amplitude, is basically a distance from midline/baseline to the maximum or minimum point.

For sine function, can be written as:

\displaystyle \large{ y = A \sin(bx  -  c) + d}

  • A = amplitude
  • b = period = 2π/b
  • c = horizontal shift
  • d = vertical shift

I am not able to provide an attachment for an easy view but I will try my best!

We know that amplitude or A is a distance from baseline/midline to the max-min point.

Let's see the example of equation:

\displaystyle \large{y = 2 \sin x}

Refer to the equation above:

  • Amplitude = 2
  • b = 1 and therefore, period = 2π/1 = 2π
  • c = 0
  • d = 0

Thus, the baseline or midline is y = 0 or x-axis.

You can also plot the graph on desmos, y = 2sinx and you will see that the sine graph has max points at 2 and min points at = -2. They are amplitude.

So to conclude or say this:

If Amplitude = A from y = Asin(x), then the range of function will always be -A ≤ y ≤ A and have max points at A; min points at -A.

6 0
3 years ago
Can someone answer this pls
pashok25 [27]
The first should be 80 the second part of it should be 210 idk if thats completely right sorry if I'm wrong i hope i helped a little
7 0
3 years ago
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