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3 years ago

The difference when 7 less than a number is subtracted from twice the number 12. What is that number?

Mathematics

1 answer:

Anvisha [2.4K]3 years ago

6 0

Answer:

The number is 19

Step-by-step explanation:

7 less than a number = x - 7

2x - x - 7 = 12

Subtract x from 2x

x - 7 = 12

Add 7 to both sides of the equation

x = 19

The number is 19

Hope this helps :)

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2 years ago

Read 2 more answers

The average annual income I in dollars of a lawyer with an age of x years is modeled with the following function I=425x^2+45,500

natali 33 [55]

You did not include the questions, but I will give you two questions related with this same statement, and so you will learn how to work with it.

Also, you made a little (but important) typo.

The right equation for the annual income is: I = - 425x^2 + 45500 - 650000

1) Determine the youngest age for which the average income of a lawyer is $450,000

=> I = 450,000 = - 425x^2 + 45,500x - 650,000

=> 425x^2 - 45,000x + 650,000 + 450,000 = 0

=> 425x^2 - 45,000x + 1,100,000 = 0

You can use the quatratic equation to solve that equation:

x = [ 45,000 +/- √ { (45,000)^2 - 4(425)(1,100,000)} ] / (2*425)

x = 38.29 and x = 67.59

So, the youngest age is 38.29 years

2) Other question is what is the maximum average annual income a layer can earn.

That means you have to find the maximum for the function - 425x^2 + 45500x - 650000

As you are in college you can use derivatives to find maxima or minima.

+> - 425*2 x + 45500 = 0

=> x = 45500 / 900 = 50.55

=> I = - 425 (50.55)^2 + 45500(50.55) - 650000 = 564,021. <--- maximum average annual income

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3 years ago

Reyesburg Corporation is contemplating using a new, more expensive glue in the construction of its laminated veneer lumber. Of i

Leokris [45]

Answer:

The mean carrying load of the beams tested is 908.7 pounds per square foot

Step-by-step explanation:

1. Data class 1: 860-879

Midpoint 1: M1=(860+879)/2=1,739/2→M1=869.5

Number of values in data class 1: n1=2

2. Data class 2: 880-899

Midpoint 2: M2=(880+899)/2=1,779/2→M2=889.5

Number of values in data class 2: n2=5

3. Data class 3: 900-919

Midpoint 3: M3=(900+919)/2=1,819/2→M3=909.5

Number of values in data class 3: n3=10

4. Data class 4: 920-939

Midpoint 4: M4=(920+939)/2=1,859/2→M4=929.5

Number of values in data class 4: n4=6

5. Data class 5: 940-959

Midpoint 5: M5=(940+959)/2=1,899/2→M5=949.5

Number of values in data class 5: n5=1

Mean=Sum(Mi*ni)/Sum(ni)

Mean=(M1*n1+M2*n2+M3*n3+M4*n4+M5*n5)/(n1+n2+n3+n4+n5)

Mean=(869.5*2+889.5*5+909.5*10+929.5*6+949.5*1)/(2+5+10+6+1)

Mean=(1,739+4,447.5+9,095+5,577+949.5)/(24)

Mean=(21,808)/(24)

Mean=908.6666666

Rounding to one decimal place:

Mean=908.7

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4 years ago