Answer:
The solution is attached below:
Step-by-step explanation:
Answer:
Step-by-step explanation:x<-5/2
I took the liberty of finding for the complete question.
And here I believe that the problem asks for the half life of Curium. Assuming
that the radioactive decay of Curium is of 1st order, therefore the
rate equation is in the form of:
A = Ao e^(-kt)
where,
A = amount after t years = 2755
Ao = initial amount = 3312
k = rate constant
t = number of years passed = 6
Therefore the rate constant is:
2755/3312 = e^(-6k)
-6k = ln (2755/3312)
k = 0.0307/yr
The half life, t’, can be calculated using the formula:
t’ = ln 2 / k
Substituting the value of k:
t’ = ln 2 / 0.0307
t’ = 22.586 years
or
t’ = 22.6 years
Answer:
0 < y ≤ 72.
Step-by-step explanation:
We are given the maximum length of the tray is 12 inches. This implies that;
x + 5 ≤ 12
x ≤ 7
Therefore, the maximum value of x is 7 inches. The maximum width will thus be;
x - 1 = 7 - 1 = 6 inches.
The maximum area, y, will thus be;
Area = length * width
Area = 12 * 6 = 72
The reasonable domain will thus be;
0 < y ≤ 72.
The area is simply between 0 and 72. The area of any object can not be negative.
Answer:
June - August
Step-by-step explanation:
First count all of the Temperature values!
1. 40 + 45 + 58 + 69 + 78 + 88 + 92 + 90 + 82 + 70 + 57 + 45 = 814
2. now divided by the amount of months!
3. the average answer is 66 and 67!
Mmm, I'm stuck in this point! Just try June - August
But this is how you can find the average with a graph!
