A derangement of rooks. Eight mutually antagonistic rooks are placed randomly on a standard chessboard with all arrangements equ
ally likely. Determine the probability that no rook can capture any other rook (that is to say, that each rook occupies a distinct row and column of the chessboard).
1 answer:
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Answer:
The statement by Ed is TRUE.
Step-by-step explanation:
Here, the given expression is:
Now, simplifying the given expression for the value of m, we get:
... (1)
Now, the answer given by Jim is
And answer stated by Ed is m = 3/8
Here, from(1) we can see that : m = 3/8
and also, m ≠ 8/3
Hence, The statement by Ed is TRUE.