Answer:
figure 1 - 10.5 unit^2
figure 2 - 12 unit^2
Step-by-step explanation:
<u>figure 1</u>
1. find the area of the rectangle
<em>3*2 = 6 unit^2</em>
2. find the area of the triangle
<em>(3*3)/2 = 4.5 unit^2</em>
3. add the area of the rectangle and the area of the triangle together. The sum would be the area of the trapezoid.
<em>6 + 4.5 = </em><u><em>10.5 unit^2</em></u>
<u>figure 2</u>
1. find the area of the rectangle
<em>2*4 = 8 unit^2</em>
2. find the area of both triangles
<em>(1*4)/2 = 2 unit^2</em>
3. add the area of the rectangle and the area of both triangles together. The sum would be the area of the trapezoid.
<em>8 + 2 + 2 = </em><u><em>12 unit^2</em></u>
Answer:
so 16 is the answer
Step-by-step explanation:
8 x 2 = 16
Answer:
20
Step-by-step explanation:
You would do this by dividing 43 into 860
Given that
and ![f(n)=[f(n-1)]^2-n](https://tex.z-dn.net/?f=f%28n%29%3D%5Bf%28n-1%29%5D%5E2-n)
We need to determine the value of f(4)
To determine the value of f(4), we need to know the values of the previous terms f(2), f(3).
<u>The value of f(2):</u>
The value of f(2) can be determined by substituting n = 2 in the function ![f(n)=[f(n-1)]^2-n](https://tex.z-dn.net/?f=f%28n%29%3D%5Bf%28n-1%29%5D%5E2-n)
Thus, we get;
![f(2)=[f(2-1)]^2-2](https://tex.z-dn.net/?f=f%282%29%3D%5Bf%282-1%29%5D%5E2-2)
![f(2)=[f(1)]^2-2](https://tex.z-dn.net/?f=f%282%29%3D%5Bf%281%29%5D%5E2-2)
![f(2)=2^2-2](https://tex.z-dn.net/?f=f%282%29%3D2%5E2-2)
![f(2)=2](https://tex.z-dn.net/?f=f%282%29%3D2)
Thus, the value of f(2) is 2.
<u>The value of f(3):</u>
The value of f(3) can be determined by substituting n = 3 in the function ![f(n)=[f(n-1)]^2-n](https://tex.z-dn.net/?f=f%28n%29%3D%5Bf%28n-1%29%5D%5E2-n)
Thus, we get;
![f(3)=[f(3-1)]^2-3](https://tex.z-dn.net/?f=f%283%29%3D%5Bf%283-1%29%5D%5E2-3)
![f(3)=[f(2)]^2-3](https://tex.z-dn.net/?f=f%283%29%3D%5Bf%282%29%5D%5E2-3)
![f(3)=2^2-3](https://tex.z-dn.net/?f=f%283%29%3D2%5E2-3)
![f(3)=1](https://tex.z-dn.net/?f=f%283%29%3D1)
Thus, the value of f(3) is 1.
<u>The value of f(4):</u>
The value of f(4) can be determined by substituting n = 4 in the function ![f(n)=[f(n-1)]^2-n](https://tex.z-dn.net/?f=f%28n%29%3D%5Bf%28n-1%29%5D%5E2-n)
Thus, we get;
![f(4)=[f(4-1)]^2-4](https://tex.z-dn.net/?f=f%284%29%3D%5Bf%284-1%29%5D%5E2-4)
![f(4)=[f(3)]^2-4](https://tex.z-dn.net/?f=f%284%29%3D%5Bf%283%29%5D%5E2-4)
![f(4)=1^2-4](https://tex.z-dn.net/?f=f%284%29%3D1%5E2-4)
![f(4)=-3](https://tex.z-dn.net/?f=f%284%29%3D-3)
Thus, the value of f(4) is -3.
F(x)=x-4
<span>x f(x)
3 –1
4 0
5 1
6 2</span>