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3 years ago

9

5 questions!!! 6 total but the last question will be separate will be giving 35 points to correct answer. Links will be ignored.

I will mark brainliest!

1 answer:

ki77a [65]3 years ago

4 0

Answer:

Step-by-step explanation:

1)down 8 up 10

2)11.2

3)9+9+9+9+9=45

4)middle

5)77.0

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HELPPPPPPPPPPP!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Vlada [557]

Answer:

the input for all is add 4

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

In need of geometry help, once again my stupid brain cant remember anything.

melomori [17]

You cannot rely on the drawing alone to prove or disprove congruences. Instead, pull out the info about the sides and angles being congruent so we can make our decision.

The diagram shows that:

Side AB = Side XY (sides with one tick mark)
Side BC = Side YZ (sides with double tickmarks)
Angle C = Angle Z (similar angle markers)

We have two pairs of congruent sides, and we also have a pair of congruent angles. We can't use SAS because the angles are not between the congruent sides. Instead we have SSA which is not a valid congruence theorem (recall that ambiguity is possible for SSA). The triangles may be congruent, or they may not be, we would need more information.

---------------

So to answer the question if they are congruent, I would say "not enough info". If you must go with a yes/no answer, then I would say "no, they are not congruent" simply because we cannot say they are congruent. Again we would need more information.

3 0

3 years ago

If a new data point at 12 is added to the graph , which will be true ?

Orlov [11]

Answer:

3. The mean will increase more than median, but both will increase.

Step-by-step explanation:

We have been given a dot plot. We are asked to find the true statement, if a new data point at 12 is added to our given dot plot.

Since we know that an large valued outlier affects mean more than median, so mean will increase more than median.

Let us check this using our given information. Our data set before adding 12 is:

1, 2, 2, 2, 3, 4, 4, 4, 5.

We can see that our data set has odd number (9) of data points, so median will be the value of 5th term, that is 3.

$\text{Mean}=\frac{1+2+2+2+3+4+4+4+5}{9}$

$\text{Mean}=\frac{27}{9}=3$

Therefore, mean of our data set is 3.

Upon adding a data point at 12, our new data set will be:

1, 2, 2, 2, 3, 4, 4, 4, 5, 12.

Now our data set has 10 terms, so median will be the average of 5th and 6th term.

$\text{Median}=\frac{3+4}{2}$

$\text{Median}=\frac{7}{2}=3.5$

Therefore, the median of new data set will be 3.5.

$\text{Mean}=\frac{1+2+2+2+3+4+4+4+5+12}{10}$

$\text{Mean}=\frac{39}{10}$

$\text{Mean}=3.9$

Therefore, mean of new data set will be 3.9.

Upon looking at our given statements we can see that 3rd statement is true as mean and median both increased after adding 12 to our data set, but mean increased more that median. Mean and median before adding 12 was 3; but after adding 12 median became 3.5, while mean became 3.9 (which is greater than mean).

3 0

3 years ago

Read 2 more answers

Find a polynomial of the form

Sloan [31]

Answer:

$f(x)=-\frac{1}{4}x^3-\frac{1}{6}x^2+\frac{65}{12}x-3$

Step-by-step explanation:

We are given that

$f(x)=ax^3+bx^2+cx+d$

f(0)=-3,f(1)=2,f(3)=5 and f(4)=0

We have to find the polynomial

Substitute the value x=0 then ,we get

f(0)=d=-3

Substitute x=1 then we get

$a+b+c-3=2$

$a+b+c=2+3=5$

$a+b+c=5$ (equation I)

Substitute x=3 then we get

$a(3)^3+b(3)^2+c(3)-3=5$

$27a+9b+3c=5+3=8$

$27a+9b+3c=8$ (Equation II)

Substitute x=4 then we get

$a(4)^3+b(4)^2+c(4)-3=0$

$64a+16b+4c=3$ (Equation III)

Equation I multiply by 3 then subtract from equation II

$24a+6b=-7$ (Equation IV)

Equation II multiply by 4 and equation III multiply by 3 and subtract equation II from III

$84a+12b=-23$ (Equation V)

Equation IV multiply by 2 and then subtract from equation V

$36a=-9$

$a=-\frac{9}{36}$

$a=-\frac{1}{4}$

Substitute the value of a in equation IV then we get

$24(-\frac{1}{4})+6b=-7$

$-6+6b=-7$

$6b=-7+6=-1$

$b=-\frac{1}{6}$

Substitute the value of b in equation I then we get

$-\frac{1}{4}-\frac{1}{6}+ c=5$

$-\frac{5}{12}+c=5$

$c=5+\frac{5}{12}=\frac{65}{12}$

Substitute the values then we get

$f(x)=-\frac{1}{4}x^3-\frac{1}{6}x^2+\frac{65}{12}x-3$

5 0

4 years ago

Quadrilateral PQRS is inscribed in a circle, as shown. Which statement is true?

Valentin [98]

The answer is C

P is half of QRS
R is half of SPQ
<span>so angles P and R are complementary.</span>

4 0

3 years ago

Read 2 more answers