The product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650 and the final product is 50327
<h3>How to determine the product of the numbers?</h3>
The numbers are given as
853 and 59
By using the standard algorithm i.e. the partial product method, we have the following equation
853 * 59 = 853 * (50 + 9)
Open the bracket
So, we have
853 * 59 = 853 * 50 + 853 * 9
Evaluate the products
So, we have
853 * 59 = 42650 + 7677
The above means that the product of multiplying the ones digit of 59 by 853 is 7677 and the product of multiplying the tens digit of 59 by 853 is 42650
Next, we evaluate the sum
853 * 59 = 50327
This means that the final product is 50327
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Simple, rewrite this equation, in y=mx+b form.
Move over the 5x, making it look like, -y=-5x+14
Then, just simply divide by the negative one in front of the y.
y=5x-14.
Answer:
3.95 and -3.95
Step-by-step explanation:
To graph a circle you can use the formula or (x – h)^2 + (y – k)^2 = r^2. So substituting in the given, we get x^2+y^2=49/pi. The x intercept is when y=0. So x^2=49/pi and so
x = sqrt(49/pi) and rounding to the nearest tenth, we get 3.95 and -3.95 because it isn’t a principal square root.
Answer:
Exactly 1.30725 bags are needed to cover the garden.
Step-by-step explanation:
We have a yard with a surface of 1307.25 square feet.
We know that one bag of fertilizer covers 1000 square feet.
We want to know how many bags are needed to cover the garden. We can calculate the number of bags as:
B: number of bags needed for the yard.
S: surface of the yard.
b: number of bags per square foot.
D.
f(x) can be written as (x+2)(x-2)(x-1)
by using difference of two squares to expand x^2 - 4 whch yields 3 x intercepts
similarly, k(x) can be written as
x(x+5)(x-5) which also yields 3
x intercepts (0,-5, and 5)
