Explain more plez i dont under shand this anymore
The first five terms of the sequence are -8, -5/8, 0, 5/64 and 16/125
<h3>Recursive form of a sequence</h3>
Given the nth term of a sequence expressed as:
an= n^2-9/ n^3
Determine the first five terms
If n = 1
a1 = 1^2-9/ 1^3
a1 = -8/1
a1 = -8
If n = 2
a2 = 2^2-9/ 2^3
a2 = -5/8
If n = 3
a3= 3^2-9/ 1^3
a3 = 9-9/3^3
a3 = 0
If n = 4
a4 = 4^2-9/ 4^3
a4= 16-9/64
a4 = 5/64
If n = 5
a5 = 5^2-9/ 1^3
a5 = 25-9/5^3
a5 = 16/125
Hence the first five terms of the sequence are -8, -5/8, 0, 5/64 and 16/125
Learn more on recursive function here: brainly.com/question/489759
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Answer:
Now 7 remains without a pair and therefore 7 should be multiplied to 112 to make it a perfect square. Similarly 28 should be multiplied to 784 to make it a perfect cube.
Answer:
A= 45 degrees
And angle B= = 135 degrees
Step-by-step explanation:
Supplementary means that the sum of both angles is equal to 180 degrees.
< A= x
< B= 3x
<a+<B= 180
x+3x= 180
4x= 180
x= 180/4
x= 45
Therefore angle A= 45 degrees
And angle B= 3x= 3*45= 135 degrees
