All categories

2 years ago

Tim is 35 years old. He is 7 years younger than 6 times his daughter's age. The equation,

Mathematics

2 answers:

nadya68 [22]2 years ago

7 0

6x-7≈35

or,6x=35+7

or,6x≈42

or,x=42÷6

x≈7

Oksana_A [137]2 years ago

6 0

Answer:

A. 7 years old

Step-by-step explanation:

6x-7=35 is the equation.

Add 7 to both sides, which gives you 6x=42.

Then both sides by 6, so 6/6=x and 42/6=7

So, x=7.

Since x is his daughter's age, x=7, so his daughter is 7.

You might be interested in

How many years will it take James to recover his investment?

My name is Ann [436]

I don’t think anyone knows this one not even James

6 0

2 years ago

A group of friends wants to go to the amusement park. They have $469.75 to spend on parking and admission. Parking is $10.75, an

attashe74 [19]

Answer:

Step-by-step explanation:

469.75-10.75 =

459 ÷ 38.25 =

8 0

2 years ago

Andrea is selling candles as a fundraiser. She spent $50 on supplies for making the candles. She plans to sell the candles for $

Kipish [7]

Answer:

A reasonable range for the function is $[0, +\infty)$ .

Step-by-step explanation:

Revenues are positive quantities since Andrea is looking for money after expenses, so that reasonable range of the revenue function is $[0, +\infty)$ .

5 0

3 years ago

The measures of the angles in an equilateral triangle are equal.

JulijaS [17]

Answer:

c.60°

Step-by-step explanation:

A triangle has 3 angles. Sum of angles in a triangle is 180 degrees. Three angles of an equilateral triangle are equal

So 180/3 = 60

7 0

3 years ago

5. 3x + 5y + 5z =1<br> x - 2y = 5<br> 2x + 4y = 11

lilavasa [31]

Answer:

see explanation

Step-by-step explanation:

Given the 3 equations

3x + 5y + 5z = 1 → (1)

x - 2y = 5 → (2)

2x + 4y = 11 → (3)

Use (2) and (3) to solve for x and y

Multiply (2) by 2

2x - 4y = 10 → (4)

Add (3) and (4) term by term

4x = 21 ( divide both sides by 4 )

x = $\frac{21}{4\\}$

Substitute this value of x into (3)

2 × $\frac{21}{4\\}$ + 4y = 11

$\frac{21}{2\\}$ + 4y = 11 ( subtract $\frac{21}{2\\}$ from both sides )

4y = $\frac{1}{2}$ ( divide both sides by 4 )

y = $\frac{1}{8\\}$

Substitute the values of x and y into (1) and solve for z

3 × $\frac{21}{4\\}$ + 5 × $\frac{1}{8\\}$ + 5z = 1

$\frac{63}{4}$ + $\frac{5}{8}$ + 5z = 1

$\frac{131}{8}$ + 5z = 1 ( subtract $\frac{131}{8}$ from both sides )

5z = - $\frac{123}{8}$ ( divide both sides by 5 )

z = - $\frac{123}{40}$

Solution is

x = $\frac{21}{4\\}$ , y = $\frac{1}{8\\}$ , z = - $\frac{123}{40}$

3 0

3 years ago