Find the midpoint of the segment with the given endpoints. D(1, 2) and E(5,

Halfway through the season, a soccer player has made 15 penalty kicks in 19 attempts. Based on her performance to date, what i

stepladder [879]

Answer:

$\dfrac{15}{19}$

Step-by-step explanation:

The soccer player so far has made 15 penalty kicks in 19 attempts.

Therefore:

Total Number of trials =19

Number of Successes =15

Therefore, the relative frequency probability that she will make her next penalty kick is:

$=\dfrac{\text{Number of Successes}}{\text{Total Number of Trials}} \\=\dfrac{15}{19}$

7 0

3 years ago

How do you solve x^2-16=0

kvasek [131]

kamsned hardy jafru 1234

4 0

4 years ago

Read 2 more answers

Is anyone can do this?

exis [7]

Answer:

Surface of $35,875.86 cm^2$

Voliume of $234,671.58 cm^3$

Long and painful calculations

Ok, this is going to take some time. The volume is the sum of all the solids, minus the half cylinder that makes the "tunnel" beneath it. That said, we can split the item into 3 main shapes, and the cylinder: The pyramid in the top left, the square based prism below the pyramid, and the trapezoid prism to the right. I edited a bit the image with paint to add measurements. It's paint so quality is what it is and deal with comic sans as a font.

Let's find the total surface first. We have the surface of the four faces of the pyramid, which are triangles of base 54 and height (red line) $\sqrt{36^2+(\frac{54}2)^2} =\sqrt{2025}=45cm$ , givins us a total area of $4\times \frac{bh}2 = 2\times 45\times 54 = 4860 cm^2$

We add the two lateral faces of the left prism: they are two rectangles of side length 70 and 54, for a total area of $2(70)(54) = 7580 cm^2$

Take the rectangle to the side of the prism, of sides 54 and 70-34 = 36, giving an area of $54\times 36 = 1944 cm^2$

Pick the inclined "roof" of the right prism, again a rectangles, sides 54 and 61: surface is $3294 cm^2$

Two side faces of the right building: first pick the height (magenta line), with pythagorean theorem again, equal to $\sqrt{ 61^2-11^2} = \sqrt{3600} = 60 cm$ . The surface becomes $2 \frac{(B+b)h}2 = (34+45)(60)= 4740 cm^2$

Missing the short sides and the half cylinder making the gallery. The sides - if you imagine un-hinging one and attaching to the bottom of the other - will make a rectangle of sides (45+70) cm and 54 cm with a circular hole in the middle. surface is $(45+70)\times54 - \pi(54/2)^2 =$ $3920.94 cm^2$ .

Finally, the half cylinder. It's a "rectangle) tall (60+54) cm - the length of the whole contraption, and long half the circle, or $27\pi$ . It's surface is $(60+54)\times\27\pi = 9664.92 cm^2$

Done with surfaces. At this point we just add everything together. Grab a calculator and start adding up, if I didn't miss anything the total surface will be $35875.86 cm^2$

Volumes now. You wished this was over? I totally did.

Bulk of the calculations are done luckly. It's just to cut and paste here and there.

Pyramid first. We know the side length, we know the height, volume is the usual formula

$\frac 13l^2h = \frac 13 54^2\times 36= 33,048 cm^3$

Cube beneath. This one is also easy Sides are 54cm, 54cm and 70cm, volume is their product:

$54*54*70= 204,120 cm^3$

Side prism now: again base surface times height, let's use the trapezoid as a base since we already have the area from above:

$A_th = 2370\times54 = 127,980 cm^3$

From this we take <u>half</u> a cylinder of radius 27 tall as the whole structure is long. $\frac12 \pi r^2h = \frac12 \pi (27)^2(60+54) = 130,476.42 cm^3$

We're done. Let's add the volume of the first 3 solids and subtract the last one - hope you have your calculator handy, to get in total a volume of $234,671.58 cm^3$

Double and triple check numbers, even if I rand them with excel.

6 0

3 years ago

The chance of a hurricane hitting during any year in the area victor will move to is 0.10 . what is the probability victor will

xeze [42]

Answer:

10^-5 or 1/100,000

Step-by-step explanation:

That probability of 5 events in a row is the 5th power of the probability of one of them, assuming they are independent.

0.1^5 = (10^-1)^5 = 10^-5

5 0

3 years ago

Cyrus runs on a track at a constant speed of 200 meters per minute. Later, he makes a graph of his run to show his coach. He put

Andrej [43]

Answer:

We know that Cyrus runs at a constant speed, then we can model this with a linear relationship.

A linear relationship can be written as:

y = a*x + b

where a is the slope and b is the y-axis intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

In the graph, we can see two points, and those are:

(0, 0) and (1, 200)

Then the slope of this line will be:

a = (200 - 0)/(1 - 0) = 200

y = 200*x + b

And to find the value of b, we just can replace the values of one of the points in the equation (for example, i will use the point (0,0) ) and get:

0 = 200*0 + b

0 = b

Then the equation is:

y = 200*x

Now we can answer the questions:

What points does he plot to show how far he runs in 8 minutes?

Here we must replace x by 8 in the equation:

y = 200*8 = 1600

Then this point will be (8, 1600)

What points does he plot to show how far he runs in 12 minutes?

Here we must replace x by 12 in the equation:

y = 200*12 = 2400

Then this point will be (12, 2400)

6 0

3 years ago

Find the midpoint of the segment with the given endpoints. D(1, 2) and E(5, –2)