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3 years ago

A man sold a square field of side 35 m and a

Mathematics

1 answer:

Novosadov [1.4K]3 years ago

6 0

Answer:

Total area of field sold(35*35)+(51*25)=2500

Area of square field is 2500

One side = $\sqrt{a}$ = 50

So, the perimeter of the square(4*a)=4*50=200

Cost of fencing = 200*1.5 usd = $300

Step-by-step explanation:

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PLEASE ANWSER CORRECTLY!! I WILL MARK BRAINIEST!!!

tankabanditka [31]

Answer:

$x = 10°$

$z = 66°$

Step-by-step explanation:

$(9x - 24)° + (12x - 6)° = 180°\\21x° - 30° = 180° \\ 21 x° = 180° + 30° \\ 21x° = 210° \\ x° = \frac{180°}{30°} \\ x° = 10°$

z° = 9x - 24 ( vertically opposite )

z° = 9(10) - 24

z° = 90 - 24

z° = 66°

<h3>Hope it is helpful.....</h3>

3 0

3 years ago

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What’s the correct answer for this question?

erma4kov [3.2K]

Answer:

Step-by-step explanation:

Perpendicular => so it will have a slope of negative reciprocal to this slope

Slope = 2/3

Now

Point = (x,y) = (6,5)

So,

x = 6, y = 5

Substituting in the slope intercept form

5 = (2/3)(6)+b

5 = 4+b

=> b = 1

So, we have

m = 2/3

b = 1

Putting in the slope intercept equation

y = 2/3x+1

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3 years ago

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3 years ago

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3 years ago

Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a

Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$