Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
2 answers:
replace n with 1, 4 and 10 and solve the equations:
answers would be D. –6, 12, 48
-6+(1-1)*6 = -6
-6+(4-1)*6 = 12
-6+(10-1)*6 = 48
The firs term
A(1)=-6+(1-1)(6)
A(1)=-6+(0)(6)
A(1)=-6
The fourh term
A(n)=-6+(n-1)(6)
A(4)=-6+(4-1)(6)
A(4)=-6+(3)(6)
A(4)=-6+18
A(4)=12
The tenth term
A(10)=-6+(10-1)(6)
A(10)=-6+(9)(6)
A(10)=-6+54
A(10)=48
Answer:
D. -6,12,48
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The awnser to the question is B