Answer:
∠ADB = γ/2 +90°
Step-by-step explanation:
Here's one way to show the measure of ∠ADB.
∠ADB = 180° - (α + β) . . . . . sum of angles in ΔABD
∠ADB + (2α +β) + γ + (2β +α) = 360° . . . . . sum of angles in DXCY
Substituting for (α + β) in the second equation, we get ...
∠ADB + 3(180° - ∠ADB) + γ = 360°
180° + γ = 2(∠ADB) . . . . . . add 2(∠ADB)-360°
∠ADB = γ/2 + 90° . . . . . . . divide by 2
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To find angles CXD and CYD, we observe that these are exterior angles to triangles AXB and AYB, respectively. As such, those angles are equal to the sum of the remote interior angles, taking into account that AY and BX are angle bisectors.
Answer:
it would be 17
Step-by-step explanation:
<span>Simplifying
X + 12 = 30
Reorder the terms:
12 + X = 30
Solving
12 + X = 30
Solving for variable 'X'.
Move all terms containing X to the left, all other terms to the right.
Add '-12' to each side of the equation.
12 + -12 + X = 30 + -12
Combine like terms: 12 + -12 = 0
0 + X = 30 + -12
X = 30 + -12
Combine like terms: 30 + -12 = 18
X = 18
Simplifying
X = 18</span>
4t<span>²
= 4(3)</span><span>²
= 4 x 9
= 36</span>