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3 years ago

What’s the circumference of this shape?xx

Mathematics

1 answer:

VikaD [51]3 years ago

7 0

The hypotenuse of the triangle would be the diameter of the semi circle.

Using the Pythagorean theorem you can find that.

8^2 + 6^2 = x^2

64 +36 = x^2

100 = x^2

x = √100

x = 10

The diameter is 10, now find the circumference.

Circumference = diameter x PI = 10 x 3.14 = 31.4

Since it is a semi circle, the circumference would be 1/2 of that.

31.4 / 2 = 15.7

The perimeter would be 8 + 6 + 15.7 = 29.7

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Answer the question

Mandarinka [93]

Answer:36

Step-by-step explanation:

6 x 12 = 72, then halved, which leaves you with 36

3 0

3 years ago

Duffy was analyzing the trajectory made after throwing a football. his coach was able to measure that his throw reached a maximu

gregori [183]

Answer:

4.35 seconds.

Step-by-step explanation:

Let x represent the time the independent variable and y be dependent variable (height of the ball).

We are told that Duffy figured that the ball left his hand at a height of 5 feet. This means at x equals 0, y was 5 or initial height of ball is 5 feet.

We have been given that Duffy's coach measured that his throw reached a maximum height of 18 feet after 2 seconds. This means that at x equals 2 y was 18.

As point (2,18) represents maximum height of ball, so it will be vertex of parabola.

Since initial height of ball is less than maximum height, so our parabola will be downward opening and leading coefficient will be negative.

We know that vertex form of a downward opening parabola is in form: $y=-a(x-h)^2+k$

$y=-a(x-2)^2+18$

Let us find value of a using point (0,5).

$5=-a(0-2)^2+18$

$5=-a*4+18$

$5-18=-a*4+18-18$

$-13=-4a$

$\frac{-13}{-4}=\frac{-4a}{-4}$

$\frac{13}{4}=a$

Therefore, the equation $y=-(\frac{13}{4})(x-2)^2+18$ can be used to find the height of ball after x seconds.

To find the time it will take the ball to hit the ground, we will substitute y equals 0 in our equation.

$0=-(\frac{13}{4})(x-2)^2+18$

$0-18=-(\frac{13}{4})(x-2)^2+18-18$

$0-18=-(\frac{13}{4})(x-2)^2$

$-18*(\frac{4}{13})=-(x-2)^2$

$\frac{72}{13}=(x-2)^2$

Taking square root of both sides of our equation we will get,

$\sqrt{\frac{72}{13}}=x-2$

$x-2\pm 2.35339$

$x-2=2.35339\text{ (or) } x-2=2.35339$

$x-2+2=2.35339+2\text{ (or) } x-2+2=-2.35339+2$

$x=4.35339\text{ (or) } x=-0.35339$

$x\approx 4.35\text{ (or) } x\approx -0.35$

Since time can not be negative, therefore, the ball will hit the ground approximately after 4.35 seconds.

7 0

3 years ago

V=s^2+1/2sh solve for h

wariber [46]

First, you separate the h variable by subtracting s^2 on both sides of the equation, getting
V - s^2 = sh/2
Then, all you have to do is divide both sides by s/2, so you get
h = 2*(v - s^2)/s as your final answer.

8 0

3 years ago

Question 3-17 i really stink at math :( it just doesnt make sense to me. alsi im failing. plz help

Trava [24]

Answer:

Step-by-step explanation:

graph is a sad face, therefore a is negative. so 1 and 3 are out. the c is the y intercept, and the y intercept is at tye positve side. so 4 is the correct one.

6 0

2 years ago

PLEASE HELP FOR 87 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!

Anton [14]

1. You can expand the coefficients to yield 6, and add the powers since the bases are the same (ie A)

2. y⁻² can also be rewritten as 1/y², so it becomes 1/y² · 1/y⁵ = 1/y⁷ (ie C)

3. Only the x is affected by the power.

4. y = 3·5ˣ doesn't change in slope, so it essentially is similar to a 5ˣ graph.

5. Should be pretty straight forward.
6. Should be pretty straight forward.
7. Should be pretty straight forward.

8. Since x is the length of the border, calculate the area of the frame and subtract that from the area of the square painting. (Remember that the length of the square painting is x - 8, not x - 4)

9. Should be pretty straight forward.
11 - 25 are pretty much similar to each other.
If you have trouble, let me know and I'll walk you through it.

6 0

3 years ago

Read 2 more answers