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goldfiish [28.3K]
3 years ago
8

How do I solve this?? x = 3 y = 5 x + y + x + x + y = ? Thank You! :)

Mathematics
2 answers:
Lapatulllka [165]3 years ago
6 0
✽ We need to replace x and y with there corresponding value. 
✽ If
✽ x=3
✽ and
✽ y=5
✽ lets replace.
✽ Starting with x
✽ 3+y+3+3+y
✽ Now Y
✽ 3+5+3+3+5
✽ Now add
✽ 19 is your answer.
✽Merry Christmas!✽

erastova [34]3 years ago
5 0
To solve this we will substitute for each letter and then add. First lets substitute for x. 

⛄x = 3
⛄3 + y + 3 + 3 + y = ? 

❄Now we will substitute for y. 

⛄y = 5
⛄x + 5 + x + x + 5 =?

❄Now lets substitute each number. 

⛄x = 3
⛄y = 5
⛄3 + 5 + 3 + 3 + 5 = 19

So, 3 + 5 + 3 + 3 + 5 (x + y + x + x + y) = 19.

Hope I helped ya!! 

❅❊Merry Christmas❅❊
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Nataly_w [17]

Answer:

m = 10\sqrt 3

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Step-by-step explanation:

Required

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Considering the given angle, we have:

\sin(60) = \frac{Opposite}{Hypotenuse}

This gives:

\sin(60) = \frac{m}{20}

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So, we have:

m = 20 *\frac{\sqrt 3}{2}

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This gives:

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5 0
2 years ago
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tigry1 [53]

Answer:

x=-1\text{ or }x=11

Step-by-step explanation:

For a=|b|, we have two cases:

\begin{cases}a=b,\\a=-b\end{cases}

Therefore, for 18=|15-3x|, we have the following cases:

\begin{cases}18=15-3x,\\18=-(15-3x)\end{cases}

Solving, we have:

\begin{cases}18=15-3x, -3x=3, x=\boxed{-1},\\18=-(15-3x), 18=-15+3x, 33=3x, x=\boxed{11}\end{cases}.

Therefore,

\implies \boxed{x=-1\text{ or }x=11}

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Answer:

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Step-by-step explanation:

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Answer:

I'll help out a bit:

Step-by-step explanation:

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