State the slope and Y intercept of this problem X =1

Spencer drink 2/3 liter of water Monday before going jogging he drink 5/7 liter of water after his jog how much water did Spence

Alenkasestr [34]

Answer:

1 8/21 liters

Step-by-step explanation:

4 0

3 years ago

How do you convert between fractions, decimals, and percentages?

svlad2 [7]

To convert to percent from fraction you divide the numerator by the denominator. from percent to decimal you move two decimal places to the left.

5 0

3 years ago

Read 2 more answers

Which logarithmic equation is equivalent to the exponential equation below?<br><br> 7^x=21

Irina-Kira [14]

Log base 7 (21)=x
Hope this helps!

7 0

3 years ago

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SUPER EASY FOR POINTS!!!!solve: x-3=3x-2

Savatey [412]

Answer:

Polynomial equation solver

x-3=3x-2

Standard form:

−2x − 1 = 0

Factorization:

−(2x + 1) = 0

Solutions:

x = −1

2

= -0.5

3 0

3 years ago

A Pew Internet poll asked cell phone owners about how they used their cell phones. One question asked whether or not during the

EastWind [94]

Answer:

a) $\hat p=\frac{471}{1024}=0.460$

The standard error is given by:

$SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156$

And the margin of error is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305$

b) The 99% confidence interval would be given by (0.429;0.491)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Data given and notation

n=1024 represent the random sample taken

X=471 represent the people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

$\hat p=\frac{471}{1024}=0.460$ estimated proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

p= population proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.