I'll be 26, and have had my daughter at 22.
Just as my mom had me at 16.. I would ask my mom for help; as I have never done it before. Although I know nothing about raising a kid I will try my best to help her, shape her, feel confident, know her worth, and her beauty. Although I wouldn't be the best mom i would still try for my daughter.
Ex; 1.. Learn how to ride a bike with mommy, I would put training wheels on my bike, aswell as hers. We would slowly progress to no training wheels. Everytime she gets frustrated I tell her " practice makes perfect" I would then say " Alright d/n (daughter name) lets pretend that that there is someone following us, and if we stop they are going to be tickling us. So lets go we dont want to be tickled right d/n? " " Are you tired yet? " " Unt Unt, mommy, can we try with no training wheels?" d/n says. I would shake my head and take the wheels off. " Look moma im doing it!" Then I would start smiling , " Good job d/n remember to focus ok? Try your best to focus" * D/N gets off* " Great job D/N lets go get some ice cream to celebrate your hard work."
SORRY I GOT CARRIED AWAY WITH THIS I WAS ABOUT TO WRITE A WHOLE LIFE STORY IMAOOOO
The main big one would be disease and infections. Trench fever, trench foot and trench mouth were common diseases people got when involved in trench warfare. Trench foot happens when the feet are exposed for long periods of time to cold water and mud. Trench fever is caused when body ice transfers from one place to another. Overcrowding conditions make this prone to happen. It causes headaches, sore muscles, skin lesions on the chest and backs as well as fever.
I hope this helps :)
(1) The integral is straightforward; <em>x</em> ranges between two constants, and <em>y</em> ranges between two functions of <em>x</em> that don't intersect.

(2) First find where the two curves intersect:
<em>y</em> ² - 4 = -3<em>y</em>
<em>y</em> ² + 3<em>y</em> - 4 = 0
(<em>y</em> + 4) (<em>y</em> - 1) = 0
<em>y</em> = -4, <em>y</em> = 1 → <em>x</em> = 12, <em>x</em> = -3
That is, they intersect at the points (-3, 1) and (12, -4). Since <em>x</em> ranges between two explicit functions of <em>y</em>, you can capture the area with one integral if you integrate with respect to <em>x</em> first:

(3) No special tricks here, <em>x</em> is again bounded between two constants and <em>y</em> between two explicit functions of <em>x</em>.
