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3 years ago

PLEASE HELP ME ASAP 50 POINTS AND BRAINLIEST!!!!!!

Mathematics

1 answer:

Virty [35]3 years ago

7 0

Answer:

The first shape is triangle; area of a triangle = 1/2*b*h

= 1/2*7*3

= 1/2*21

= 21/2

= 10.5

The second shape is rectangle; area of rectangle = l*b

= 7*3

= 21

Total area:

10.5+21

= 31.5

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Solve both by substitution method (algebra 2) and show work please<br><br> -2x-7y=22<br>-7x-5y=-1

Alex17521 [72]

$\bf \begin{cases}
-2x-7y=22\\
-7x-5y=-1
\end{cases}\qquad \textit{let's solve the \underline{second one} for "x"}
\\\\\\
-7x-5y=-1\implies -7x=5y-1\implies x=\cfrac{5y-1}{-7}
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\boxed{x=\cfrac{1-5y}{7}}\impliedby \textit{now, let's substitute it in the \underline{first one}}
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$\bf -2\left( \frac{1-5y}{7} \right)-7y=22\implies \cfrac{10y-2}{7}-7y=22
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\textit{now, let's multiply both sides by 7, to toss the denominator}
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\textit{now, let's use that in the \underline{first one}}
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4 0

3 years ago

Find a1 if Sn = 89,800, r = 3.4, and n = 10. Round to the nearest hundredth if necessary.

xxMikexx [17]

Answer:

$a_1=1.04$

Step-by-step explanation:

We have a geometric sequence with:

$Sn = 89,800$ , $r = 3.4$ , and $n = 10$

Where

Sn is the sum of the sequence

r is the common ratio

$a_1$ is the first term in the sequence

n is the number of terms in the sequence

The formula to calculate the sum of a finite geometric sequence is:

$S_n=\frac{a_1(1-r^n)}{1-r}$

Then:

$89,800=\frac{a_1(1-(3.4)^{10})}{1-3.4}$

Now we solve for $a_1$

$89,800(1-3.4)=a_1(1-(3.4)^{10})$

$a_1=\frac{89,800(1-3.4)}{1-(3.4)^{10}}\\\\a_1=1.04$

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