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3 years ago

Can anyone help me, with at least the first one?

Mathematics

1 answer:

kirza4 [7]3 years ago

3 0

3. r^2 + 2r - 35 4. a^2- 11a + 28
(r + 7)(r - 5) (a - 7)(a - 4)

5. m^2 - 6m - 7 6. m^2 - m - 2
(m + 1)(m - 7) (m - 2)(m + 1)

7. n^2 - 4n + 3 8. b^2 - 4b - 5
(n - 3)(n - 1) (b - 5)(b + 1)

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Help!! Please im having trouble

bekas [8.4K]

Answer:

1. 5/6 ≥ 2/3

2. 1/5 ≤ 2/8

3. 9/10 ≥ 6/8

4. I can't see it's out of the pic

5. 7/8 ≥ 5/10

6. 2/5 ≥ 2/6

7. 1/3 ≤ 3/8

8. I can't see it's out of the pic.

9. 8/10 ≥ 3/4

10. 3/8 ≤ 11/12

11. 2/3 ≤ 10/12

12. Can't see :(

13. 3/8 ≤ 7/8

14. 2/4 = 4/8

15. 6/8 ≥ 8/12

16. Can't see

Step-by-step explanation: All you have to do is divide the numerator by the denominator to make it into a decimal. For instance....

5/6 = approximately 0.83

I hope this helps you! It took forever....

3 0

3 years ago

Does anyone have the solution to this

klasskru [66]

Step-by-step explanation:

There is 1 root at x = 1, where the function crosses the x-axis.

There are 2 roots at x = -2, where the function touches the x-axis but does not cross.

So there are 3 real roots total.

The function is:

y = (x − 1) (x − (-2))²

y = (x − 1) (x + 2)²

6 0

4 years ago

Write these in decimals <br><br> 5/100

77julia77 [94]

0.05

The 5 is in the hundredth place.

7 0

4 years ago

Read 2 more answers

Use the given conditions to write an equation for the line in point-slope form. Passing through (2,-3) with x-intercept = -2

goldfiish [28.3K]

The equation for line is $y=-\frac{3}{4} x-\frac{3}{2}$

Explanation:

It is given that the line passes through the point $(2,-3)$ with x-intercept = -2

The x intercept is the value of x when y = 0.

Thus, it can be written in coordinate as $(-2,0)$

Now, we shall determine the slope using the points $(2,-3)$ and $(-2,0)$

$m=\frac{y_2-y_1}{x_2-x_1}$

Substituting, we get,

$m=\frac{0+3}{-2-2} \\m=-\frac{3}{4}$

Thus, the slope is $m=-\frac{3}{4}$

Now, we shall substitute the point $(2,-3)$ and slope $m=-\frac{3}{4}$ in the point-slope formula $y-y_1=m(x-x_1)$ , we get,

$y+3=-\frac{3}{4} (x-2)$

Multiplying both sides by 4, we get,

$4y+12=-3x+6$

Subtracting both sides by 12,

$4y=-3x-6$

Dividing both sides by 4, we get,

$y=-\frac{3}{4} x-\frac{3}{2}$

Thus, the equation of the line is $y=-\frac{3}{4} x-\frac{3}{2}$

4 0

4 years ago

The triangles are similar. Find the value of x =

Naily [24]

1 1/7 2 4/5kskskkskskksks

4 0

3 years ago