Answer:
Cost of one roll of plain wrapping: 
Cost of one roll of holiday wrapping paper: 
Step-by-step explanation:
Let be "p" the cost in dollars of one roll of plain wrapping paper and "h" the cost in dollars of one roll of holiday wrapping paper.
Based on the information given, we can set up this system of equations:

In order to solve it, we can use the Substitution method. The steps are:
1. Solve for "p" from the first equation:

2. Substitute the above into the second equation and solve for "h":
3. Substitute the value of "h" into
:

Answer:
v=whl 1 7/8 × 2 3/4 × 3 1/2 = 18 3 \64
Answer:
Step-by-step explanation:
2a + 6 / a² -9 = 2(a + 3) / (a² -3²)
= 2(a+3) / (a+3)(a-3) {a²-b² = (a+b)(a-b)
= 2 / (a-3)
Answer:
The expression represents a second degree polynomial with two terms The constant term is 1/8 deleting term is x² and the leading coefficient is 6
Answer:
y=salary=32.000
x=years
salary after 15 years y+1800x
32000+1800(15)
32000+27000=59000
Step-by-step explanation: