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Olenka [21]
3 years ago
8

A network administrator is reviewing a network design that uses a fixed configuration enterprise router that supports both LAN a

nd WAN connections. However, the engineer realizes that the router does not have enough interfaces to support growth and network expansion. Which type of device should be used as a replacement to avoid having the same problem in the future
Computers and Technology
1 answer:
tester [92]3 years ago
8 0

Answer:

a modular router

Explanation:

A modular router is a type of router that will provide multiple slots, this will enable the network engineer to either change or increase the number of space the router has.

A layer 3 switch cannot provide a WAN connectivity even though it can increase the number of ports on a router. The concept of PoE capability of any device have nothing to do with the number of ports it has. If the Engineer decides to use another fixed configuration router it will still lead to the same problem in the future because it cannot guarantee or provide the flexibility of future growth adaptation which can be given by a modular router if put in use.

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Answer:

import java.util.Scanner;

import java.util.Random;

public class Solution

{

public static void indexEven(int[] randomNumbers)

{

System.out.print("Even index elements are: ");

for (int i = 0; i < randomNumbers.length; i++)

{

if (i % 2 == 0)

{

System.out.print(randomNumbers[i] + " ");

}

}

System.out.println();

}

public static void evenelement(int[] randomNumbers)

{

System.out.print("Every even element: ");

for (int i = 0; i < randomNumbers.length; i++)

{

if (randomNumbers[i] % 2 == 0)

{

System.out.print(randomNumbers[i] + " ");

}

}

System.out.println();

}

public static void reverseOrder(int[] randomNumbers)

{

System.out.print("All elements in reverse order: ");

for (int i = randomNumbers.length - 1; i >= 0; i--)

{

System.out.print(randomNumbers[i] + " ");

}

System.out.println();

}

public static void firstLast(int[] randomNumbers)

{

System.out.print("First and last elements are: ");

System.out.print(randomNumbers[0] + " " + randomNumbers[randomNumbers.length - 1]);

System.out.println();

}

public static void main(String[] args)

{

// create instance of Random class

Random rand = new Random();

System.out.print("Array: ");

int[] randomNumbers = new int[10];

for (int i = 0; i < randomNumbers.length; i++)

{

randomNumbers[i] = rand.nextInt(100);

System.out.print(randomNumbers[i] + " ");

}

System.out.println();

indexEven(randomNumbers);

evenelement(randomNumbers);

reverseOrder(randomNumbers);

firstLast(randomNumbers);

}

}

Explanation:

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