The answer to the question
Given expression in exponential form : 
.
We need to convert it into radical form.
<em>Please note: When we convert an exponential to radical form, the top number goes in the exponent of the term and bottom number of the fraction goes in the radical sign to make it nth radical.</em>
We can apply following rule:
![(a)^{\frac{m}{n}}= \sqrt[n]{x^m}](https://tex.z-dn.net/?f=%28a%29%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D)
.
Therefore,
![a^{\frac{4}{9} }= \sqrt[9]{a^4}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7B4%7D%7B9%7D%20%7D%3D%20%5Csqrt%5B9%5D%7Ba%5E4%7D)
.
Therefore, correct option is : D. ninth root of a to the fourth power.
Answer:
a(10) = 170
Step-by-step explanation:
Given that,
The nth term fo the sequence is :
a(n) = n² + 7n
We need to find the 10th term of the sequence.
Put n = 10 in the above sequence,
a(10) = (10)² + 7(10)
= 100 + 70
= 170
So, the 10th term of the sequence is 170.
Answer:
- c(n) = 320·0.96^n
- 28 years
Step-by-step explanation:
Each year, the class size is multiplied by 1 - 4% = 96% = 0.96. After n years, it has been multiplied by that number n times. Repeated multiplication is signified using an exponent.
Class size (c) can be modeled by ...
c(n) = 320·0.96^n
__
You want to find n such that c(n) = 100. Put in that value and solve.
100 = 320·0.96^n
100/320 = 0.96^n . . . . . . . divide by 320
log(100/320) = n·log(0.96) . . . . . . . take logs
log(100/320)/log(0.96) = n ≈ 28.4932
In about 28 years, the class will have 100 students.
Y= - 8/5 first you subtract 10 from 18 and than divide by negative 5
