Question

Write an equation in slope intercept form for the trend line shown below.

Answer 1

Step-by-step explanation:

Given line is passing through the points (3, 60) & (6, 50)

Therefore, slope of line:

$m = \frac{50 - 60}{6 - 3} = - \frac{10}{3} \\ y - intercept \: (b) = 70 \\ equation \: of \: line \: in \: slope \: intercept \\ form \: is \: given \: as : \\ y = mx + b \\ \huge \red{ \boxed{\therefore \: y = - \frac{10}{3} x + 70}} \\ which \: is \: the \: required \: equation.$

Answer 2

Answer:

Step-by-step explanation:

Slope-Intercept form is y=mx+b

m is the slope and b is the y-intercept

You can use any ordered pairs but I suggest ones that touch down on an intersect like (0,70) and (3,60)

slope=$\frac{y^{2} -y^{1} }{x^{2} -x^{1} }$

slope using (0,70) and (3,60)=$-\frac{10}{3}$

The y-intercept is 60 since its the number that touches the y-axis

So the equation for the trend line is

$y=-\frac{10}{3} x+70$