Answer:
0.9115 is the proportion of paint cans that contain less than 5.54 ml of the dye.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 5 ml
Standard Deviation, σ = 0.4 ml
We are given that the distribution of amount of dye dispensed is a bell shaped distribution that is a normal distribution.
Formula:
P(paint cans contain less than 5.54 ml of the dye)
Calculation the value from standard normal z table, we have,
0.9115 is the proportion of paint cans that contain less than 5.54 ml of the dye.
Answer:
21 1/6 ft
Step-by-step explanation:
Add the lengths together
12 1/2 + 8 2/3
Get a common denominator of 6
12 1/2 *3/3 + 8 2/3 *2/2
12 3/6 + 8 4/6
20 7/6
20 +6/6+1/6
21 1/6
Answer:
5/12
Step-by-step explanation:
The whole book is 1.
So This will be your equation.
1/3 + 1/4 = 1
4/12 +3/12 = 1
7/12 = 1
Now you minus 7/12 from 1
1-7/12 is how much is left
12/12-7/12= 5/12
We are required to find the total milligrams if medicine the hospital can get from the three companies.
The total quantity of medicine the hospital can get from the three companies is 2.75 milligrams
There are there companies:
Company A
Company B
Company C
Company A = 1.3 milligrams
Company A is 0.9 milligrams more than Company C's
A = 0.9 + C
1.3 = 0.9 + C
1.3 - 0.9 = C
0.4 = C
C = 0.4 milligrams
Company A is also twice the difference between the weight of
Company B's supply and Company C's
A = 2(B - C)
1.3 = 2(B - 0.4)
1.3 = 2B - 0.8
1.3 + 0.8 = 2B
2.1 = 2B
Divide both sides by 2
B = 2.1/2
B = 1.05 milligrams
Therefore,
A + B + C
= 1.3 + 1.05 + 0.4
= 2.75 milligrams
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