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2 years ago

Please help with the questions. Thank you.

Mathematics

1 answer:

IrinaVladis [17]2 years ago

4 0

Answer:

1. Isolate

2. Closed

3. Reversed

If you have more problems with things similar to this, I recommend this website, it gives a detailed description on how to solve the equations:

https://www.mathsisfun.com/algebra/inequality-solving.html

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(V. An aeroplane is flying parallel to the Earth's surface at a speed of 175 m/sec and at a height of 600 m. The angle of elevat

GREYUIT [131]

dot on top of earth = plane position at the time of observation (right one when 37°, left one 53°)

then the geometry is zoomed on the left side

4 0

2 years ago

How many times can 5 go into 1620

kaheart [24]

1620/ 5 is =324
To check just multiply
5 * 324

5 0

2 years ago

10 ounces for $2.40 is a better deal than 8 ounces for $2.08. 2 SEE ANSWERS

Natasha2012 [34]

Answer:

2.40/10 = 0.24 per Oz

2.08/8 = 0.26 per Oz.

so yes, 10 Oz. for 2.40 is a better deal

Step-by-step explanation:

your are welcome

6 0

1 year ago

Read 2 more answers

A square has a side length of 10cm. Work out the length of a diagonal of the square.

Vitek1552 [10]

Answer: Let x = the length of a side of the square

a2 + b2 = c2

x2 + x2 = 102

2x2 = 100

x2 = 50

x = √50

x = 5√2 cm

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

True or false. Tan^2 x = 1 - cos2x/ 1 + cos 2x

koban [17]

ANSWER

True

EXPLANATION

The given trigonometric equation is

$\tan^{2} (x) = \frac{1 - \cos(2x) }{1 + \cos(2x) }$

Recall the double angle identity:

$\cos(2x) = \cos^{2} x - \sin^{2}x$

We apply this identity to obtain:

$\tan^{2} (x) = \frac{1 - (\cos^{2} x - \sin^{2}x) }{1 + (\cos^{2} x - \sin^{2}x) }$

We maintain the LHS and simplify the RHS to see whether they are equal.

Expand the parenthesis

$\tan^{2} (x) = \frac{1 - \cos^{2} x + \sin^{2}x }{1 + \cos^{2} x - \sin^{2}x}$

$\implies\tan^{2} (x) = \frac{1 - \cos^{2} x + \sin^{2}x }{1 - \sin^{2}x + \cos^{2} x }$

Recall that:

$1 - \sin^{2}x = \cos^{2}x$

$1 - \cos^{2}x = \sin^{2}x$

We apply these identities to get:

$\implies\tan^{2} (x) = \frac{\sin^{2}x + \sin^{2}x }{\cos^{2} x + \cos^{2} x }$

$\implies\tan^{2} (x) = \frac{2\sin^{2}x }{ 2\cos^{2} x }$

$\implies\tan^{2} (x) = \frac{\sin^{2}x }{ \cos^{2} x }$

$\implies \tan^{2} (x) =( \frac{\sin x }{ \cos x })^{2}$

Also

$\frac{\sin x }{ \cos x } = \tan(x)$

$\implies \tan^{2} (x) =( \tan x )^{2}$

$\implies \tan^{2} (x) =\tan^{2} (x)$

Therefore the correct answer is True

5 0

2 years ago