The ratio of the area of ∆ABC to the area of ∆DEF is; 1:100.
<h3>What is the ratio of the area of ∆ABC to the area of ∆DEF?</h3>
Since, a major criterion for similarity and congruence of triangles is that the ratio of corresponding sides are equal.
On this note, since the task content suggest that the ratio of the perimeters is; 1:10, it follows from conventional mathematics that the ratio of their areas is given as; 1²:10²; 1:100.
Read more on congruent triangles;
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Cross multiply the denominators by the numerators. In other words, 12 times 3 and 7 times x (x, being our missing number).
We end up with 36 and 7x.
Divide both sides by 7.
36/7x = 5.14
x = 5.14
Hope this helps!
The first step is to quickly factor each of the five equations... to do so, find the right factors of the 3rd given number so that they add up in an equal number to the second number... 14 = -7 • -2 and -9 = -7 + -2
a^2 - 9a + 14 = 0
(a - 7) (a - 2)
a - 7 = 0, a = 7
a - 2 = 0, a = 2
{2,7}
a^2 + 9a + 14 = 0
(a + 7) (a + 2)
a + 7 = 0, a = -7
a + 2 = 0, a = -2
{-2, -7}
a^2 + 3a - 10 = 0
(a + 5) (a - 2)
a + 5 = 0, a = -5
a - 2 = 0, a = 2
{-5, 2}
a^2 - 5a - 14 = 0
(a - 7) (a + 2)
a - 7 = 0, a = 7
a + 2 = 0, a = -2
{-2, 7}
Answer:0,1,2
Step-by-step explanation:every x
