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rewona [7]
3 years ago
8

Dr. W Sweet Rides Car Rental charges a flat fee of $24 and an additional $0.35 for every mile the car is driven. Which function

models the total cost, C(x), of renting a car for x miles?
If you drive 40 miles, how much can you expect to pay?
Mathematics
1 answer:
kompoz [17]3 years ago
3 0

Step-by-step explanation:

this is a strange rental company charging no daily fees.

but ok.

so, we have a fixed part of the cost : $24

we have to pay that no matter how many miles we drive. even for 0 miles, just to get the keys to the car.

and then we pay $0.35 for every mile driven.

that makes our function

C(x) = 0.35x + 24

and if we drive 40 miles, that makes x = 40.

C(24) = 0.35×40 + 24 = 14 + 24 = $38

it would cost us $38.

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What is the probability that he will hit fewer than 8 of the bottles?
torisob [31]

Using the binomial distribution, it is found that the probability that he will hit fewer than 8 of the bottles is of 0.012, given by option A.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, we have that:

  • The probability of a bottle being hit is of p = 0.95.
  • There are n = 10 bottles.

The probability that he hits fewer than 8 of the bottles is given by:

P(X < 8) = 1 - P(X \geq 8)

In which:

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.95)^{8}.(0.05)^{2} = 0.0746

P(X = 9) = C_{10,9}.(0.95)^{9}.(0.05)^{1} = 0.3151

P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987

Hence:

P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.0746 + 0.3151 + 0.5987 = 0.988

P(X < 8) = 1 - P(X \geq 8) = 0.012

The probability that he will hit fewer than 8 of the bottles is of 0.012, given by option A.

More can be learned about binomial distribution at brainly.com/question/24863377

#SPJ1

7 0
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