Question

How mamy moles of NaCl will be produced from 83.0g pf Na, assuming Cl2 is available in excess

Answer 1

Answer:

3.61mole of NaCl

Explanation:

Given parameters:

Mass of  Na = 83g

Unknown:

Number of moles of NaCl produced = ?

Solution:

We write the reaction equation first;

       2Na    +   Cl₂    →    2NaCl

Since Cl₂ is in excess in this reaction, the extent will be determined by how much Na is available.

find the number of Na and relate to that of NaCl

 Number of moles of Na  = $\frac{mass}{molar mass}$

          molar mass of Na = 23g/mole

                                            = $\frac{83}{23}$    

                                            = 3.61mole

          2 mole of Na    reacted  with 2 mole of NaCl

         3.61 mole of Na will react with 3.61mole of NaCl