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adoni [48]
4 years ago
9

if 3 1/2 cups of flour are used with 1 1/4 cups of brown sugar, how much sugar is used when 10 1/2 cups of flour is used?​

Mathematics
1 answer:
pickupchik [31]4 years ago
3 0
Step by step equation
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Matt was given the problem: "16 is 80% of what?"
irga5000 [103]

Answer:

\frac{16}{x} = \frac{80}{100}  

Step-by-step explanation:

To set up this proportion, we know that 16 must correspond with 80% and the x, the number we're looking for must correspond with 100%

\frac{16}{x} = \frac{80}{100}

This would be the correct proportion, and you could simplify it to equal

\frac{16*100}{80}

3 0
3 years ago
HELP ASAP PLEASE!
Genrish500 [490]

Step-by-step explanation:

lets take a look....

In order to find the perimeter of a triangle you have to get the sum of all sides. In other words,

Blue triangle:

p = (4x +2) + (7x + 7) + (5x  - 4) \\ p = 4x + 2 + 7x + 7 + 5x - 4 \\ p = 16x + 5

Red triangle:

p = (x + 3) + (2x - 5) + (x + 7) \\ p = x + 3 + 2x - 5 + x + 7 \\ p = 4x + 5

Difference:

d = (16x + 5) - (4x + 5) \\ d = 16x + 5 - 4x - 5 = 12x \\ d = 12x

4 0
3 years ago
Evaluate 13+ 6/y when y=6
liubo4ka [24]

Answer: 14

Step-by-step explanation:

13 + 6/6 = ?

13 + 1 = 14

3 0
3 years ago
Can anybody help me?
Marina CMI [18]

Answer:

I’m sorry. I don’t know the answer but if u take a picture it on photomath u will get the answer

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The length s(t)s(t)s, (, t, )of the side of the base of a square prism is decreasing at a rate of 777 kilometers per minute and
gavmur [86]

Answer:

\frac{dA_{s}}{dt} = -148\,\frac{km^{2}}{min}

Step-by-step explanation:

The surface area of the square prism is obtained by using the following formula:

A_{s} (t) = 4\cdot l(t)\cdot h(t) + 2\cdot [l(t)]^{2}

The rate of change of the surface area can be found by deriving the function with respect to time:

\frac{dA_{s}}{dt} = 4\cdot [h(t)\cdot \frac{dl}{dt} + l(t)\cdot \frac{dh}{dt}] + 2\cdot l(t)\cdot \frac{dl}{dt}

Known variables are summarized below:

h(t) = 9\,km

l(t) = 4\,km

\frac{dh}{dt} = 10\,\frac{km}{min}

\frac{dl}{dt} = -7\,\frac{km}{min}

The rate of change is:

\frac{dA_{s}}{dt} = 4\cdot [(9\,km)\cdot (-7\,\frac{km}{min} )+(4\,km)\cdot (10\,\frac{km}{min} )] + 2\cdot (4\,km)\cdot (-7\,\frac{km}{min} )

\frac{dA_{s}}{dt} = -148\,\frac{km^{2}}{min}

3 0
3 years ago
Read 2 more answers
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