Please help ASAP :)))))

Mathematics

1 answer:

3241004551 [841]3 years ago

6 0

Answer:1. it is number 3 2. the second one 3. it is the first one

Step-by-step explanation:

You might be interested in

How do you find slope intercept from a graph

Makovka662 [10]

The slope intercept is equal to the rise/run.

So lets say to get from one point to the other, you go down 2 units and go right 3 units.

Since you went down it is a -2. If you had gone up 2 units, then it would be a positive 2.

Since you went to the right, it is a positive 3. If you had gone left 3 units, then it would be -3.

-2/3

4 0

3 years ago

For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12

notsponge [240]

The binomial distribution is given by,
P(X=x) = $(^{n}C_{x})p^{x} q^{n-x}$
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = $(^{100}C_{x})(0.2)^{x} (0.8)^{100-x}$
where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12
∴ P(X≤12) = $(^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1}$ + $(^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3}$ + $(^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5}$ + $(^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7}$ + $(^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9}$ + $(^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11}$ + $(^{100}C_{12})(0.2)^{12} (0.8)^{100-12}$

Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability.

7 0

3 years ago

24. Analyze Relationships There are three numbers a, b, and c, where a > b

mestny [16]

Answer:

A-is farthest to the right on the number line

B-in the middle of the number line

C- farthest to the left on the number line

Step-by-explanation

If we have 3 random numbers we can conclude that a<c so we can say

A is farthest to the right

B in the middle