If x = 2 and y = -3, what is the value of 2x^2−3xy−2y^2 HELPPP
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Answer:
C'(4,4)
Step-by-step explanation:
The dilation of quadrilateral ABCD over the origin by a scale factor of 2 has the rule
(x,y)→(2x,2y)
So,
- A(-3,-1)→A'(-6,-2)
- B(-1,1)→B'(-2,2)
- C(2,2)→C'(4,4)
- D(3,-2)→D'(6,-4)
Hence, the coordinates of the image point C' are (4,4) (see attached diagram for details)
