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Nastasia [14]
3 years ago
11

If x = 2 and y = -3, what is the value of 2x^2−3xy−2y^2 HELPPP

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
8 0

Answer:

8

Step-by-step explanation:

2(2)^2‒3(2*‒3)‒2(‒3)^2

2*4‒3(‒6)‒2(9)

8‒(‒18)‒18

8+18‒18

26‒18

8

i think it is easy to understand &i hope it will helps you

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the answer I'd 1.008

Step-by-step explanation:

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What is the equation in standard form of the line Y equals 1 / 9 x + 5
Juli2301 [7.4K]

Answer:

1/9x - y = -5

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra I</u>

Standard Form: Ax + By = C

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define equation</u>

Slope-Intercept Form:   y = 1/9x + 5

<u>Step 2: Find Standard Form</u>

  1. Subtract 1/9x on both sides:                    -1/9x + y = 5
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4 0
3 years ago
Use the function below to find F(3).
Vaselesa [24]
<span>F(x) = (1/4)^x

</span><span>F(3) = (1/4)^3 = 1/64

</span><span>B. 1/64</span>
8 0
3 years ago
Read 2 more answers
Solve quadratic formulax^2-4x+3=0
bekas [8.4K]

The general formula for a equation of the form:

ax^2+bx+c=0

is:

x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

In this case we notice that a=1, b=-4 and c=3. Plugging this values in the general formula we get:

\begin{gathered} x=\frac{-(-4)\pm\sqrt[]{(-4)^2-4(1)(3)}}{2(1)} \\ =\frac{4\pm\sqrt[]{16-12}}{2} \\ =\frac{4\pm\sqrt[]{4}}{2} \\ =\frac{4\pm2}{2} \end{gathered}

then:

x_1=\frac{4+2}{2}=\frac{6}{2}=3

and

x_2=\frac{4-2}{2}=\frac{2}{2}=1

Therefore, x=3 or x=1.

8 0
1 year ago
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