Answer:
The answer is 13/3.
Step-by-step explanation:
8 2/3 is an improper fraction and is expressed as 26/3. CCF (copy, change, flip) is then applied to the division statement and 26/3 to becomes 4/8*26/3. The final answer is 104/24 which simples to 13/3.
Answer:
Jack in Zeta Labs near Facility Intelligence and Zeta Labs spawn (Sells gadgets like the Presence Reduction Module and Night Vision Goggles)
Step-by-step explanation:
Answer:
8
Those little "sticks" are called absolute value.
For example, the absolute value of 2 is 2, and the absolute value of −2 is also 2. The absolute value of a number may be thought of as its distance from zero along real number line.
Thus, it doesn't matter if the number is positive or negative. As it only counts its <u>d</u><u>i</u><u>s</u><u>t</u><u>a</u><u>n</u><u>c</u><u>e</u><u> </u><u>f</u><u>r</u><u>o</u><u>m</u><u> </u><u>0</u><u>,</u><u> </u><u>o</u><u>n</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>l</u><u>i</u><u>n</u><u>e</u><u>.</u>
I hope it helps.
a = 4, b = -21, c = -18
to keep from getting "mixed up", evaluate the discriminant first ...
b<sup>2</sup> - 4ac = (-21)<sup>2</sup> - 4(4)(-18) = 729
sqrt(729) = 27
x = (21 +/- 27)/8
x = -3/4, x = 6
since the discriminant is a perfect square, the original quadratic will factor ...
4x<sup>2</sup> - 21x - 18 = 0
(4x + 3)(x - 6) = 0
x = -3/4, x = 6
A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?
Answer:

Step-by-step explanation:
Given:
A stuntman jumping off a 20-m-high building is modeled by the equation
-----------(1)
A high-speed camera is ready to making film between 15 m and 10 m above the ground
when the stuntman is 15m above the ground.
height
Put height value in equation 1





We know that the time is always positive, therefore 
when the stuntman is 10m above the ground.
height
Put height value in equation 1







Therefore ,time interval of camera film him is 