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defon
3 years ago
14

What is the slope of a line parallel to the line whose equation is y - x = 5? -1 1 5

Mathematics
2 answers:
elena-s [515]3 years ago
6 0
the \ slope \ intercept \ form \ is : \\ \\ y= mx +b\\\\y - x = 5 \\ \\y=x+5 \\ \\ m=1


lord [1]3 years ago
3 0

I believe the answer is 1

sorry if I'm wrong  

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Martha and Janet each decide to invest $600 into different accounts. Martha's account earns $4.50 every month. Janet's account e
ehidna [41]

Answer:

<u>Janet's interest is $3.90 every month.</u>

Step-by-step explanation:

First, you need to set up a proportion to find Janet's interest:

0.65%/100 = x/600

Step 1: Cross-multiply.

0.65/100/100 = x/600

(0.65/100)*(600)=x*(100)

39/10=100x

Step 2: Flip the equation.

100x=39/10

Step 3: Divide both sides by 100.

100x/100=39/10/100

x=39/1000 (0.039)

Then move the decimal twice to the left to find the dollar amount:

0.039 ⇒ 3.90

Janet's interest is $3.90 every month.

HOPE THIS HELPS!!! <33333

-Silver

5 0
3 years ago
Read 2 more answers
HELP ME PLEASE AND FAST HURRY
KonstantinChe [14]

Answer:

(1,0)

Step-by-step explanation:

The vertex is the maximum of the parabola

It is at x=1 and y = 0

(1,0)

8 0
4 years ago
Read 2 more answers
Order these numbers from least to greatest. 6.2052, 6.2, 6.75, 6.705
Ad libitum [116K]

Answer:

<u>6.2 , 6.2052 , 6.705 , 6.75</u>

Step-by-step explanation:

Least to Greatest!

7 0
2 years ago
What is the value of x when 6x-20+4x+20
const2013 [10]

Answer:

6x+4x-20+20

10x-0

x=10

6 0
3 years ago
Determine the probability of selecting a two-child family with one boy and one girl assuming boys and girls are equally likely
Fittoniya [83]

Using the binomial distribution, it is found that there is a 0.5 = 50% probability of selecting a two-child family with one boy and one girl.

For each child, there are only two possible outcomes, either it is a boy, or it is a girl. The probability of a child being a boy or being a girl is independent of any other child, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • Two children, hence n = 2.
  • Equally as likely to be a boy or a girl, hence p = 0.5.

The probability of one of each is P(X = 1), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{2,1}.(0.5)^{1}.(0.5)^{1} = 0.5

0.5 = 50% probability of selecting a two-child family with one boy and one girl.

A similar problem is given at brainly.com/question/24863377

3 0
3 years ago
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