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Nat2105 [25]
2 years ago
13

Which function describes the arithmetic sequence shown?

Mathematics
1 answer:
krek1111 [17]2 years ago
5 0

Answer:

f(x) 4x-1   answer: d)

Step-by-step explanation:3.7, 11, 15, 19, 23,

hello :

23-19=19-15=15-11=11-7=7-3=4.....common diference

the first term is : 3       f(x) = 3+4(x-1)  ...genral term

f(x) 4x-1    answer: d)

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A grocer stacks oranges in a four-sided pyramid that is 7 layers high. How many oranges are in the pile?
gayaneshka [121]
Short Answer D
P(1) = 1(1+1)(2*1 + 1)/6
P(1) = 1(2)(2 +1) / 6
P(1) = 1(2)(3)/6
P(1) = 1

P(2) = 2(2+1)(2*2 + 1) / 6
P(2) = 2(3)(5) / 6
P(2) = 5 So this formula is adding as it goes along. To Find the Total all we need do is use the formula to calculate P(1) to P(7)

P(7) = 7*(7 + 1)(2*7 + 1)/6
P(7) = 7 * 8 * 15 / 6
P(7) = 7 * 4 * 5 
P(7) = 140 <<<< Answer
4 0
3 years ago
What do I do? what's Ax??
Liono4ka [1.6K]

A=\left[\begin{array}{ccc}5&-4\\3&6\end{array}\right] \\\\A_x=\left[\begin{array}{ccc}12&-4\\66&6\end{array}\right]

|A_x|=\left|\begin{array}{ccc}12&-4\\66&6\end{array}\right|=(12)(6)-(66)(-4)=72+264=336

5 0
3 years ago
Mr. Hayes has 11 straw bundles to use forr bedding in his horse stalls. What is the greatest number of stalls he can fill if eac
Svetllana [295]

Answer:

2 stalls

Step-by-step explanation:

Mr. Hayes has 11 straw bundles to use forr bedding in his horse stalls. What is the greatest number of stalls he can fill if each stall holds exactly 4 bundles

1 stall = 4 bundles

4 bundles = 1 stall

11 bundles = x

Cross Multiply

4x = 11

x = 11/4

x = 2 3/4 stalls

The greatest number of stalls he can build is 2 stalls

7 0
3 years ago
What is the pattern?
Ksju [112]

Answer:

to the left of 0 it goes up negative 1/2 and on the right side of 0 it goes up 1/2 from 0

Step-by-step explanation:

4 0
2 years ago
6th grade fractions...
blsea [12.9K]

The last pair of numbers bracket the point 3/7.

12/32 = 3/8 < 3/7

15/18 = 5/6 > 3/7

_____

3/7 ≈ 0.428571... (repeating), so will be larger than 3/8 = 0.375, 12/32 = 3/8, and 4/10. That is, 3/7 is larger than the largest number of each pair except the last.

------

You can always compare two fractions to see which is larger by cross-multiplying. That is a/b vs c/d gives the same result as ad vs bc. (Put the product on the numerator side of the comparison.)

Here, that would mean comparing 12/32 vs 3/7, we would get 12·7 vs 3·32, or 84 vs 96. The fraction on the left is smaller.

Comparing 3/7 vs 15/18, we would get 3·18 vs 7·15, or 54 vs 105. The fraction on the right is larger.

4 0
3 years ago
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