X+y=4 :x=4-y,yR
x-y=6:x=6+y,yR
I’m so so sorry I don’t know that I wish I could help but I can’t :(
Given:
The two vectors are:


To find:
The value of
.
Solution:
We have,


The cross product of these two vectors is:

![\overrightarrow{a}\times \overrightarrow{b}=\hat{i}[(-1)(5)-(1)(-3)]-\hat{j}[(2)(5)-(1)(1)]+\hat{k}[(2)(-3)-(-1)(1)]](https://tex.z-dn.net/?f=%5Coverrightarrow%7Ba%7D%5Ctimes%20%5Coverrightarrow%7Bb%7D%3D%5Chat%7Bi%7D%5B%28-1%29%285%29-%281%29%28-3%29%5D-%5Chat%7Bj%7D%5B%282%29%285%29-%281%29%281%29%5D%2B%5Chat%7Bk%7D%5B%282%29%28-3%29-%28-1%29%281%29%5D)
![\overrightarrow{a}\times \overrightarrow{b}=\hat{i}[-5+3]-\hat{j}[10-1]+\hat{k}[-6+1]](https://tex.z-dn.net/?f=%5Coverrightarrow%7Ba%7D%5Ctimes%20%5Coverrightarrow%7Bb%7D%3D%5Chat%7Bi%7D%5B-5%2B3%5D-%5Chat%7Bj%7D%5B10-1%5D%2B%5Chat%7Bk%7D%5B-6%2B1%5D)

Now the magnitude of the cross product is:



Therefore, the value of
is
.
Answer:
-2 1/6
Step-by-step explanation:
Answer:
1, 000, 000
Step-by-step explanation:
There are 6 zeros, so add them to the 1.