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xxTIMURxx [149]
3 years ago
9

IF YOU COULD CREATE A SOCIAL NETWORK:, what would it be like? What would make it so special about the others? (If you want you c

an name it)
Computers and Technology
1 answer:
frosja888 [35]3 years ago
3 0

It would be like instagram

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When you are fit, you can exercise and do physical work without getting too tired. A. True B. False\
enot [183]

Answer:

A.

Explanation:

But all of us get tired

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3 years ago
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__ means having a current knowledge and understanding of computers, mobile devices, the web, and related technologies.
Brrunno [24]

Answer:

Digital literacy

Explanation:

Digital Literacy means having a current knowledge and understanding of computers, mobile devices, the web, and related technologies.

Brainliest plz

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4 years ago
What is the difference between computer architecture and computer organization?
alukav5142 [94]
The distinction between "computer architecture" and "computer organization" has become very fuzzy, if no completely confused or unusable. Computer architecture was essentially a contract with software stating unambiguously what the hardware does. The architecture was essentially a set of statements of the form "If you execute this instruction (or get an interrupt, etc.), then that is what happens. Computer organization, then, was a usually high-level description of the logic, memory, etc, used to implement that contract: These registers, those data paths, this connection to memory, etc. Programs written to run on a particular computer architecture should always run correctly on that architecture no matter what computer organization (implementation) is used. For example, both Intel and AMD processors have the same X86 architecture, but how the two companies implement that architecture (their computer organizations) is usually very different. The same programs run correctly on both, because the architecture is the same, but they may run at different speeds, because the organizations are different. Likewise, the many companies implementing MIPS, or ARM, or other processors are providing the same architecture - the same programs run correctly on all of them - but have very different high - level organizations inside them.
8 0
3 years ago
Read 2 more answers
Program:
Mkey [24]

Answer:

See explaination

Explanation:

#method to print menu & handle user choice

def print_menu(input_str):

#printing menu

print('MENU')

print('c - Number of non-whitespace characters')

print('w - Number of words')

print('f - Fix capitalization')

print('r - Replace punctuation')

print('s - Shorten spaces')

print('q - Quit\n')

#getting choice

choice=input('Choose an option: ').lower()

#identifying choice

if choice=='c':

#displaying number of non white space chars in input_str

print('Number of non-whitespace characters:',get_num_of_non_WS_characters(input_str))

elif choice=='w':

#displaying number of words in input_str

print('Number of words:',get_num_of_words(input_str))

elif choice=='f':

#fixing capitalization and getting updated string and count of values capitalized

input_str,count=fix_capilization(input_str)

#displaying results

print('Number of letters capitalized:',count)

print('Edited text:',input_str)

elif choice=='r':

#replacing punctuation, displaying updated text

input_str=replace_punctuation(input_str)

print('Edited text:', input_str)

elif choice=='s':

#shortening spaces and displaying updated text

input_str = shorten_space(input_str)

print('Edited text:', input_str)

#returning choice and input_str

return choice,input_str

#returns the number of non white space chars in input_str

def get_num_of_non_WS_characters(input_str):

count=0

#looping through each character in input_str

for i in input_str:

if not i.isspace():

#i is not a space

count+=1

return count

#returns the number of words in input_str

def get_num_of_words(input_str):

#splitting words into list of tokens by space

words=input_str.split(' ')

count=0

#counting all non empty strings in words list

for i in words:

if len(i)>0:

count+=1

return count

#method to fix capitalization and return updated string and count of letters updated

def fix_capilization(input_str):

count=0

beginning=True #starting letter should be capitalized

result=''

for i in input_str:

if beginning and i.isalpha():

#start of a sentence and i is alphabetic

if i.islower():

#converting i to upper case, incrementing count

i=i.upper()

count+=1

result+=i

#not start of a sentence

beginning=False

elif i in '?.!':

#i is either ? or . or !, next letter should be capitalized

beginning=True

result+=i

else:

#any other character

result+=i

return result,count

#method to replace exclamation and semicolons with period and comma respectively

def replace_punctuation(input_str,exclamationCount =0,semicolonCount=0):

result=''

for i in input_str:

if i=='!':

i='.'

exclamationCount+=1

elif i==';':

i=','

semicolonCount+=1

result+=i

print('Punctuation replaced')

#displaying replaced values counts

print('exclamationCount:',exclamationCount)

print('semicolonCount:',semicolonCount)

return result

#removes all double or more spaces in input_str

def shorten_space(input_str):

input_str=input_str.strip()

result=''

prev=None

for i in input_str:

if prev==None:

result+=i

elif i==' ':

if prev != ' ':

result+=i

else:

result+=i

prev=i

return result

if __name__ == '__main__':

#getting input, printing it

input_str=input('Enter a sample text:\n')

print('\nYou entered:',input_str)

choice=' '

#looping until choice becomes q

while choice!='q':

choice,input_str=print_menu(input_str)

7 0
3 years ago
Which of the following statements is true about DVI connectors? *
Elis [28]

Answer:

I think u had forgot to mention the statements.

4 0
3 years ago
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