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nataly862011 [7]

3 years ago

8

Is 23 and 25 co-primes

1 answer:

MariettaO [177]3 years ago

7 0

Answer:

yes because they have one as a company factor

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Which of the following is TRUE about the hypotenuse?

svetoff [14.1K]

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<u>The genuine articulations of the hypotenuse of a right triangle are: It is the longest side of a right triangle, It is inverse the correct point. The genuine explanations of the hypotenuse of a right triangle are: It is the longest side of a right triangle, It is inverse the correct point</u>

4 0

2 years ago

Identify the vertical shift, maximum and minimum values of each function

Delicious77 [7]

ANSWER

Vertical shift: 6 units up

Maximum value: 9

Minimum value: 3

EXPLANATION

The given since function is

$y = 3(2 - \sin(x))$

Expand and rewrite to obtain,

$y = 6 - 3 \sin(x)$

Or

$y =- 3 \sin(x) + 6$

The vertical shift is 6 units up.

The maximum value is 6+3=9.

The minimum value is -3+6=3

5 0

3 years ago

Enter the expression using exponents. 1\2 × 1\2 × 1\2 × 1\2 × 1\2 × 1\2 × 1\2

Ad libitum [116K]

Answer:

<h2>1/2⁷</h2>

Step-by-step explanation:

1/2 is multiplied by itself 7 times, thus an exponent of 7.

I'm always happy to help :)

3 0

3 years ago

Read 2 more answers

RectangleABCD has vertices at A(– 3, 1),B(– 2, – 1),C(2, 1), andD(1, 3). What is the area, in square units, of this rectangle? A

Anna [14]

Answer:

Option A. $10\ units^{2}$

Step-by-step explanation:

we know that

The area of the rectangle is equal to

A=LW

where

L is the length of rectangle

W is the width of rectangle

we have

$A(-3,1),B(-2,-1),C(2,1),D(1,3)$

Plot the vertices

see the attached figure

L=AD=BC

W=AB=DC

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

<em>Find the distance AD</em>

$A(-3,1),D(1,3)$

substitute in the formula

$AD=\sqrt{(3-1)^{2}+(1+3)^{2}}$

$AD=\sqrt{(2)^{2}+(4)^{2}}$

$AD=\sqrt{20}$

$AD=2\sqrt{5}\ units$

<em>Find the distance AB</em>

$A(-3,1),B(-2,-1)$

substitute in the formula

$AB=\sqrt{(-1-1)^{2}+(-2+3)^{2}}$

$AB=\sqrt{(-2)^{2}+(1)^{2}}$

$AB=\sqrt{5}$

$AB=\sqrt{5}\ units$

Find the area

$A=(2\sqrt{5})*(\sqrt{5})=10\ units^{2}$

4 0

3 years ago

Julio has 1000 square ft of living space. The n he added a room that was 20 ft by 10 ft. What was the percentage increase of liv

Gemiola [76]

Answer:

Step-by-step explanation:mmmmmmm

7 0

3 years ago