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Alex777 [14]
3 years ago
15

For the function f(x)=x+9/7-4x find f^-1(x)

Mathematics
1 answer:
Liula [17]3 years ago
3 0

Answer:

Step-by-step explanation:

f(x)=\frac{x+9}{7-4x} \\put ~f(x)=y\\flip~x~and~y\\f(y)=x\\y=f^{-1}(x)\\y=\frac{x+9}{7-4x} \\flip~x~and~y\\x=\frac{y+9}{7-4y} \\x(7-4y)=y+9\\7x-4xy=y+9\\-4xy-y=9-7x\\or\\4xy+y=7x-9\\y(4x+1)=7x-9\\y=\frac{7x-9}{4x+1} \\or~f^{-1}(x)=\frac{7x-9}{4x+1}

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Because you are rounding to the hundreds, you look at the tens place. The tens place is a "1" and 1 is below five, so you round down to 200.

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X^2 - 2x = 15 how do I solve this quadratic method?<br>I am stuck on it.... please help<br>​
Anarel [89]

Answer:

(x - 5)(x + 3)

Step-by-step explanation:

to solve x² - 2x = 15, we need to get all the terms on one side so we can solve the quadratic equation using factoring. to do this, we subtract 15 from both sides

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x² - 2x - 15 = 0

now we can factor. we need 2 numbers that when multiplied together give us -15, and when those 2 numbers are added together we get -2

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FOIL stands for: First, Outside, Inside, and Last terms

F: (x - 5)(x + 3) = x²

O: (x - 5)(x + 3) = -3x

I: (x - 5)(x + 3) = 5x

L: (x - 5)(x + 3) = -15

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Step-by-step explanation:

Enjoy :)

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