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Andrei [34K]
3 years ago
5

1 liter of ink can print 5000 pages of text. If you had 100 gallons of ink then how many pages could you print?

Mathematics
2 answers:
miss Akunina [59]3 years ago
8 0

Answer:

500,000 pages

Step-by-step explanation:

1 / 5000 = 100 / x

x = 5000(100)

x = 500,000

Dominik [7]3 years ago
5 0

Answer:

1892705 pages of text.

Step-by-step explanation:

g=Gallon

L=Liters

P=Pages

1L=5000p

1g=3.78541L

100g·3.78541L=378.541L

378.541L·5000=1892705

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What you would do is take the denominators and multiply them by each other, then multiply the numerators by that same number. So like 4/10 and 4/9. You would say, (denominators) 10x9=90 and (numerators) 4x9=36. So your first fraction would be 36/90. Next, you would take (denominators) 9x10=90 and (numerators) 4x10=40. So your second fraction would become 40/90. Now it's a lot easier to compare. 36/90 < 40/90 would be the answer to my problem. I hope I helped!
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Angles X and Y are supplementary. Angle X is 3 times the measure of angle Y. What is the measure of angle X?
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</span>lets x  = measure of angle Y

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Angle X = 135
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A Tessellation has no________. A) gaps or overlaps B) translations C) repeated figures
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8 0
3 years ago
A random sample of 20 students yielded a mean of ¯x = 72 and a variance of s2 = 16 for scores on a college placement test in mat
Helen [10]

Answer:

The 98% confidence interval for the variance in the pounds of impurities would be 8.400 \leq \sigma^2 \leq 39.827.

Step-by-step explanation:

1) Data given and notation

s^2 =16 represent the sample variance

s=4 represent the sample standard deviation

\bar x represent the sample mean

n=20 the sample size

Confidence=98% or 0.98

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=20-1=19

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.01,19)" "=CHISQ.INV(0.99,19)". so for this case the critical values are:

\chi^2_{\alpha/2}=36.191

\chi^2_{1- \alpha/2}=7.633

And replacing into the formula for the interval we got:

\frac{(19)(16)}{36.191} \leq \sigma^2 \leq \frac{(19)(16)}{7.633}

8.400 \leq \sigma^2 \leq 39.827

So the 98% confidence interval for the variance in the pounds of impurities would be 8.400 \leq \sigma^2 \leq 39.827.

7 0
3 years ago
Could you pleaseee help me
vladimir1956 [14]
3.6 \times 10^{14} \times 8 \times 10^{10}

= 3.6 \times 8 \times 10^{14 + 10}

= 28.8  \times 10^{24}

= 2.88  \times 10^{25}

3 0
4 years ago
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