Answer:
See below.
Step-by-step explanation:
Draw segment OB.
In triangle OBC, points R and S are the midpoints of sides OC and BC, respectively. That makes RS parallel to OB.
In triangle OBA, points P and Q are the midpoints of sides OA and BA, respectively. That makes PQ parallel to OB.
Since segments RS and PQ are parallel to segment OB, then RS and PQ are parallel to each other.
Answer:
11
Step-by-step explanation:
Use a calculator. Punch in 5.5, then use the divide symbol (÷) and finally put in 0.5, then you will get 11 as your final answer.
Hope this helps!
Line perpendicular to a given line is = 1/m
To find m, use m =y2-y1/x2-x1 formula
m = (8-(-3))/(-7-4)
m = 11/-11,
m = -1
Use y= mx+c to find equation of line
Plug in a pair of values,
-3= -1(4)+ c
c= 1
Thus, equation is:
y = -x+1
Equation of line perpendicular to this line is:
y= x+1
Hope it helps :)
Pls mark it as Brainliest :)
Answer:
(1.37) AUB = { 1,2,3,4,5,6}
(1.38) AUC = { 1,2,3,4,5 }
(1.39)BUC = { 1,2,3,4,5,6}
(1.40) { 2,4 }
(1.41) { 1,3,5 }
(1.42) { phi }
(1.43) AU(BUC) = { 1,2,3,4,5,6 }
(1.44) { phi }
(1.45) {1,2,3,4,5}
(1.46) { 1,2,3,4,5 }
That's easy 172.1 times 10 with the exponent of 7
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