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Darya [45]
2 years ago
8

Makayla takes home $4400 per month from her job as a physical therapist. if her only debt obligations are a car loan payment of

$530 and a mortgage payment of $760 every month, is she in danger of credit overload?
Mathematics
2 answers:
AleksAgata [21]2 years ago
5 0
The total amount that Makayla needs to pay is equal to $530 + $760 which is equal to $1290. This value is lesser compared to the amount that Makayla is able to take home. Therefore, Makayla will not be in danger of credit overload and she will be able to provide for her other needs. 
poizon [28]2 years ago
4 0

No, because 530 is less than 880 APEX :)


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Using the quadratic formula, which of the following are the zeros of the
Nana76 [90]

Answer:

y=x2-X-5 is zero of quadratic equation

8 0
2 years ago
Write a x (-a)x 13 x a x (-a) x 13 in power notation
miss Akunina [59]

Answer:

a\times (-a)\times 13\times a\times (-a)\times 13 can be written in power notation as a^{4}\times 13^{2}

Step-by-step explanation:

The given expression

a\times (-a)\times 13\times a\times (-a)\times 13

Writing a\times (-a)\times 13\times a\times (-a)\times 13 in power notation:

Let

a\times (-a)\times 13\times a\times (-a)\times 13

= [13\times13][(a\times (-a)\times a\times (-a)]

As

13\times13 = 13^{2} , a\times a = a^{2} , (-a)\times (-a) = (-a)^{2}

So,

=[13^{2}][a^2\times (-a)^2]

As

(-a)^2 = a^{2}

So,

=[13^{2}][a^2\times a^2]

As ∵a^{m} \times a^{n}=a^{m+n}

=[13^{2}][a^{2+2}]

As ∵a^{m} \times a^{n}=a^{m+n}

=13^{2}\times a^{4}

=a^{4}\times 13^{2}

Therefore, a\times (-a)\times 13\times a\times (-a)\times 13 can be written in power notation as a^{4}\times 13^{2}

<em>Keywords: power notation</em>

<em>Learn more about power notation from brainly.com/question/2147364</em>

<em>#learnwithBrainly</em>

5 0
2 years ago
Help me please explain do not need work just explain THANK YOU I NEED HELP
Mnenie [13.5K]
Alright, 

you will need to solve for each variable to find if they got the equation correctly or not.. 

Let's start with h 
isolate h 
(1/2)h = A/(b1+b2)
Now we need to get rid of 1/2 we may do so by multiplying both sides by 2 

h = 2(A/(b1+b2))

And that's not how they did it for h so Option D doesn't apply 


Let's see C
Also doesn't apply since they multiplied 2 only by A rather than A/h

Let's see B
Also not correct they made the same mistake as with option C

Let's see A
again same mistake 
when multiplying both sides by 2 
the 2 should be as following 
2\frac{A}{h}

I believe you should contact your instructor and explain that non of the options is right. 

6 0
2 years ago
you eat $0.85 for every cup of hot chocolate you sell. How many cups do you need to sell to earn $55.25
Alina [70]

0.85$ for 1 cups

1$ for 1/0.85 cups

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2 years ago
Positive fractions less than 1,with interval of 1/8 between each pair of fractions
Sati [7]
Yes it is keep up the good work
4 0
3 years ago
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