Answer:
y=x2-X-5 is zero of quadratic equation
Answer:
can be written in power notation as 
Step-by-step explanation:
The given expression

Writing a\times (-a)\times 13\times a\times (-a)\times 13 in power notation:
Let

= ![[13\times13][(a\times (-a)\times a\times (-a)]](https://tex.z-dn.net/?f=%5B13%5Ctimes13%5D%5B%28a%5Ctimes%20%28-a%29%5Ctimes%20a%5Ctimes%20%28-a%29%5D)
As
,
,
So,
![=[13^{2}][a^2\times (-a)^2]](https://tex.z-dn.net/?f=%3D%5B13%5E%7B2%7D%5D%5Ba%5E2%5Ctimes%20%28-a%29%5E2%5D)
As

So,
![=[13^{2}][a^2\times a^2]](https://tex.z-dn.net/?f=%3D%5B13%5E%7B2%7D%5D%5Ba%5E2%5Ctimes%20a%5E2%5D)
As ∵
![=[13^{2}][a^{2+2}]](https://tex.z-dn.net/?f=%3D%5B13%5E%7B2%7D%5D%5Ba%5E%7B2%2B2%7D%5D)
As ∵


Therefore,
can be written in power notation as 
<em>Keywords: power notation</em>
<em>Learn more about power notation from brainly.com/question/2147364</em>
<em>#learnwithBrainly</em>
Alright,
you will need to solve for each variable to find if they got the equation correctly or not..
Let's start with h
isolate h
(1/2)h = A/(b1+b2)
Now we need to get rid of 1/2 we may do so by multiplying both sides by 2
h = 2(A/(b1+b2))
And that's not how they did it for h so Option D doesn't apply
Let's see C
Also doesn't apply since they multiplied 2 only by A rather than A/h
Let's see B
Also not correct they made the same mistake as with option C
Let's see A
again same mistake
when multiplying both sides by 2
the 2 should be as following

I believe you should contact your instructor and explain that non of the options is right.
0.85$ for 1 cups
1$ for 1/0.85 cups
55.25$ for [1/0.85]*55.25 = 55.25/0.85 = 65 cups
Yes it is keep up the good work