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lidiya [134]
2 years ago
12

Nasrin invested $6000 in a bond at a yearly rate of 3%. She earned $450 in interest. How long was the money invested?​

Mathematics
1 answer:
Alenkasestr [34]2 years ago
6 0
4 years

6000 x .3 = 1,800. 1800 divided by 450 = 4
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Examine the following equation and classify the type of solution.
Viktor [21]

Answer:

<h2>infinitely many solutions</h2>

Step-by-step explanation:

5x - 6 = 3x - 6 + 2x     <em>combine like terms</em>

5x - 6 = (3x + 2x) - 6

5x - 6 = 5x - 6         <em>subtract 5x from both sides</em>

-6 = -6        TRUE

Therefore the equation has infinitely many solutions.

5 0
3 years ago
THis is kinda hard, pls help ASAP
Feliz [49]

Answer:

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7 0
3 years ago
Use the Empirical Rule to answer each question.
Oliga [24]

Step-by-step explanation:

(a)

the probability of parcels weighing 35oz or less is

0.841

the probability of parcels weighing 14oz or less is

0.023

the probability of parcels weighing between 14 and 35oz is the probabilty of 35oz minus the probability of 14oz

0.841 - 0.023 = 0.818

the percentage is the probability × 100 = 81.8%

(b)

the probability of parcels weighing more than 49oz is 1 minus the probability to weigh less than 49oz.

the probability to weigh less than 49oz is

0.99865

so, the probability to weigh more than 49oz is

1 - 0.99865 = 0.00135

the percentage is again probability×100 = 0.14%

7 0
3 years ago
The next event requires each runner to jump 8 hurdles that are spaced 12.3 meters apart. If there are 15 meters from the startin
inessss [21]
The race is 111.6 m long.

8 hurdles spaced 12.3 m apart means 7 spaces that are 12.3 m in length; 7*12.3 = 86.1

Add to this the distance to the first hurdle and the distance from the last hurdle:
86.1+15+10.5 = 111.6 m
3 0
3 years ago
A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
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