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vfiekz [6]
4 years ago
15

A painting measures 2.4 feet from left to right. It’s hung in the center of a rectangular wall measuring 20 feet from left to ri

ght. What is the distance between the right edge of the painting and the right edge of the wall? Assume that the painting does not tilt.
Mathematics
1 answer:
julsineya [31]4 years ago
5 0
Since the painting is hung in center of a rectangular wall ,the distance between them on either side will be the same.so we can divide the length of the painting and wall by 2.we will get  2.4/2=1.2 feet and 20/2=10 feet .10-1.2=8.8 feet gives the distance between the right edge of the painting and right edge of the wall
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Answer:

\frac{b}{50} books.

Step-by-step explanation:  

We have been given that Hannah's school hosted a book donation.

Total number of students = 150.

Total number of books donated by all students = b.

Since we know that average is calculated by dividing the sum of the values in the set by their number.

\text{Average number of books donated by each student}=\frac{\text{Total number of books}}{\text{Total number of students}}

\text{Average number of books donated by each student}=\frac{b}{150}

Since we are told that Hannah donated 3 times as many as the average number of books each student donated.  So books donated by Hannah will be:

\text{Number of books donated by Hannah}=3\times\frac{b}{150}

Upon simplifying we will get,

\text{Number of books donated by Hannah}=\frac{b}{50}

Therefore, Hannah donated \frac{b}{50} books.




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