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miss Akunina [59]
4 years ago
9

How many days will it take a spaceship to accelerate from rest to the speed of light (3.0Ã108m/s) with the acceleration g?

Physics
1 answer:
tia_tia [17]4 years ago
4 0
Answer is: 354 days.
V = V₀ + g·t.
V - final velocity, V = 3·10⁸ m/s.
V₀ - initial velocity, V₀ = o, because spaceship is in rest.
t - t<span>ime, how long it takes for spaceship to move from one position to another.
</span>g - gravity, g = 9,8 m/s².
t = V÷g = 3,06·10⁷s = 510204min = 88503,4hr = 354 days.

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Se debe usar una rampa de 5 m para elevar muebles que pesen 490 N hasta una plataforma a una altura de 2 m. Su propuesta de que
AfilCa [17]

Answer:

F = 180 N

Explanation:

To find the required force you first calculate the angle of the ramp, by using the following relation:

sin\theta=\frac{2m}{5m}=0.4\\\\\theta=sin^{-1}(0.4)=23.57\°

Next, you use the Newton second law to know what is the x component (in a rotated coordinate system) of the gravitational force:

F_x=mgsin\theta

the required force must be, at least, the last force Fx. You know that the weight of the object is 490N = mg. Hence, you have:

F=F_x=(450N)sin(23.57\°)=180N

the required force is 180N

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TRANSLATION:

Para encontrar la fuerza requerida, primero calcule el ángulo de la rampa, utilizando la siguiente relación:

Luego, usa la segunda ley de Newton para saber cuál es el componente x (en un sistema de coordenadas girado) de la fuerza gravitacional:

la fuerza requerida debe ser, al menos, la última fuerza Fx. Sabes que el peso del objeto es 490N = mg. Por lo tanto, tienes:

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