Question

P(A)=7/20,P(B)=3/5,P(A∩B)=21/100 ,P(A∪B)=?

Answer 1

Answer:

P( A U B) = 37/50

Step-by-step explanation:

7/20+3/5+21/100

IF YOU NEED MORE HELP LMK

Answer 2

Answer:  The required value of P(A∪B) is $\dfrac{37}{50}.$

Step-by-step explanation:  For the two event A and B, we have the following probabilities :

$P(A)=\dfrac{7}{20},~~P(B)=\dfrac{3}{5},~~P(A\cap B)=\dfrac{21}{100}.$

We are to find the following probability :

$P(A\cup B)=?$

From the laws of probability, we have

$P(A\cup B)\\\\=P(A)+P(B)-P(A\cap B)\\\\=\dfrac{7}{20}+\dfrac{3}{5}-\dfrac{21}{100}\\\\\\=\dfrac{35+60-21}{100}\\\\\\=\dfrac{74}{100}\\\\\\=\dfrac{37}{50}.$

Thus, the required value of P(A∪B) is $\dfrac{37}{50}.$