P(A)=7/20,P(B)=3/5,P(A∩B)=21/100 ,P(A∪B)=?

Mathematics

2 answers:

satela [25.4K]3 years ago

7 0

Answer:

P( A U B) = 37/50

Step-by-step explanation:

7/20+3/5+21/100

IF YOU NEED MORE HELP LMK

il63 [147K]3 years ago

6 0

Answer: The required value of P(A∪B) is $\dfrac{37}{50}.$

Step-by-step explanation: For the two event A and B, we have the following probabilities :

$P(A)=\dfrac{7}{20},~~P(B)=\dfrac{3}{5},~~P(A\cap B)=\dfrac{21}{100}.$

We are to find the following probability :

$P(A\cup B)=?$

From the laws of probability, we have

$P(A\cup B)\\\\=P(A)+P(B)-P(A\cap B)\\\\=\dfrac{7}{20}+\dfrac{3}{5}-\dfrac{21}{100}\\\\\\=\dfrac{35+60-21}{100}\\\\\\=\dfrac{74}{100}\\\\\\=\dfrac{37}{50}.$

Thus, the required value of P(A∪B) is $\dfrac{37}{50}.$

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