1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kogti [31]
3 years ago
5

Answer plz will give brainliest to the best and correct answer :) itz only 1 question

Mathematics
2 answers:
bonufazy [111]3 years ago
4 0

Answer:

54 units²

Step-by-step explanation:

Hello! :)

I don't know which equation your teacher wants you to use for the Area of a Triangle, but this is how I do it:

A= ½(b*h)

A= ½(18*6)

A= ½ (108)

A= 54

--------------------

If you prefer an explanation in word form, here you go:

The area of a triangle is Area= one-half, multiplied by its base and height.

A= ½(b*h)

So in this question, the base(b)= 18 and the height(h)= 6.

A= ½(18*6)

Then, you just solve the math problem (shown up above)!

Good luck with your homework, and I don't need a brainliest I just wanted to help! :)

musickatia [10]3 years ago
3 0

Answer:

A = 54 units ^2

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh where b is the base and h is the height

A = 1/2 ( 18) * ( 6)

A = 54 units ^2

You might be interested in
PLEASE HELP ASAP I’LL MARK BRAINLIEST Find the area of the figure.
Sonbull [250]
Area of a semicircle is 1/2* πr^2
Area of a square is s^2


Square’s area: 4mm^2

The radius is 3mm
Plug into the equation

1/2* π(3^2)
1/2* π(9)

We can use 3.14 as an estimate of pi

1/2*28.26

14.13mm^2

Now just add them both

Total area 18.13mm^2
4 0
3 years ago
Triangle NMO has vertices at N(−5, 2), M(−2, 1), O(−3 , 3). Determine the vertices of image N′M′O′ if the preimage is reflected
Firdavs [7]

Notice that the reflection is over a line of the form x=constant; in this case, the y-coordinate of the reflected point stays the same while the x-coordinate changes as expressed by the transformation below

\begin{gathered} y\rightarrow y \\ x\rightarrow2a+x \\ where \\ x=a\rightarrow\text{ vertical line} \end{gathered}

Hence, in our case

\Rightarrow(x,y)=(2*-4-x,y)=(-8-x,y)

Transform points N, M, and O accordingly,

\begin{gathered} \Rightarrow N^{\prime}=(-8-(-5),2)=(-8+5,2)=(-3,2) \\ \Rightarrow M^{\prime}=(-8-(-2),1)=(-6,1) \\ \Rightarrow O^{\prime}=(-8-(-3),3)=(-5,3) \end{gathered}<h2>Therefore, the answer is the first option (top to bottom)</h2>

6 0
11 months ago
Please help I need you​
mario62 [17]

Answer:

The answer is B.

Step-by-step explanation:

Diameter x Pi = Circumference

8 x 3.14 = 25.12

8 0
3 years ago
Read 2 more answers
Can someone please help
Masteriza [31]
19 hours is your answer
 
8 0
3 years ago
Read 2 more answers
jorge, the shipping manager at Durable Products, writes a memo proposing that that they stop using RoadHog Trucking Company and
goblinko [34]

Answer:

If it is causing other accounts to grow also that means that they would be in competition.

Step-by-step explanation:

7 0
3 years ago
Other questions:
  • 2 more and I’m done thank y’all so much sorry I’m dumb and in 8th grade LOL
    11·2 answers
  • Need help ASAP!!!!!!
    9·1 answer
  • Hii anyone mind helping me with this question :D
    13·1 answer
  • The table represents a function.
    13·2 answers
  • Solve the inequalities for x, and match each solution to its number line graph.
    12·1 answer
  • A scuba diver is swimming 28 feet below the water’s surface. The diver swims up slowly at a rate of 0.3 feet per second for 6 se
    12·2 answers
  • -5/6 x -2/9 =<br> Do you guys know this one?
    12·2 answers
  • Atalien is 5 feet tall. His shadow is 8 feet long. At the same time of day, a tree's shadow casts a 32 feet long shadow. What is
    5·2 answers
  • Can someone pllsss help :((
    6·1 answer
  • Find the degree of 3x<br><img src="https://tex.z-dn.net/?f=3%20%7Bx%7D%5E%7B3%7D%20y%5E%7B2%7D%20" id="TexFormula1" title="3 {x}
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!