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3 years ago

If you vertically stretch the exponential function, f(x)=2^x, by a factor of 4, what is the equation of the new function?

Mathematics

2 answers:

LiRa [457]3 years ago

7 0

Answer:

f(x)=4(2)ˣ

Step-by-step explanation: to vertically strech a function by a factor of c, multiply the whole function by x

Alex777 [14]3 years ago

3 0

Answer:

g(x) = 4*2^x

Step-by-step explanation:

Stretching this expo function by a factor of 4 is equivalent to multiplying the original function by 4: g(x) = 4*2^x.

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How to convert $400.00 per week to a monthly figure

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$400 per week is $1600 per month assuming theres 4 months

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3 years ago

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Compare the graphs of the logarithmic functions f(x)= log7 (x) and g(x)=log4(x) . For what values of x is f=g , f>g, and f

densk [106]

The blue curve represents the f(x) function while the orange curve represents the g(x) function
f=g, if x<0 and f>g, if x>0

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3 years ago

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A game is played with tokens according to the following rule. In each round, the player with the most tokens gives one token to

Lelu [443]

The number of rounds that can be played is given by the product of three

and the least number of tokens a player has at the start.

<h3>Response;</h3>

<u>45 rounds</u>

<h3>Reasons for arriving at the above value;</h3>

A round is when the player with the most tokens gives one token to each of the other players, and one placed in the discard pile, we have;

<h3>First three round</h3>

17 - 3 = 14

16 + 1 = 17

15 + 1 = 16

17 - 3 = 14

14 + 1 = 15

16 + 1 = 17

17 - 3 = 14

14 + 1 = 15

15 + 1 = 16

The above values follow a number series such that we have;

<h3>Fourteenth three rounds</h3>

4 - 3 = 1

2 + 1 = 3

3 + 1 = 4

4 - 3 = 1

1 + 1 = 2

3 + 1 = 4

4 - 3 = 1

2 + 1 = 3

1 + 1 = 2

<h3>Fifteenth three rounds</h3>

3 - 3 = 0

1 + 1 = 2

2 + 1 = 3

3 - 3 = 0

0 + 1 = 1

2 + 1 = 3

3 - 3 = 0

0 + 1 = 1

1 + 1 = 2

Therefore, after the fifteenth three rounds, which is 15 × 3 = <u>45 rounds</u> Ava runs out of token, ending the game.

Learn more about number series here:

brainly.com/question/4163549

6 0

2 years ago

This is a 2 part question.

irina [24]

B
just for extra space

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3 years ago

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Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(−2, 1) and Q(8, 9)

IrinaK [193]

Answer:

Equation of the circle (x-3)²+(y-5)²=(6.4)²

x² -6x +9 +y² -10y +25 = 40.96

Step-by-step explanation:

Given endpoints of diameter P(−2, 1) and Q(8, 9)

Centre of circle = midpoint of diameter

Centre = $(\frac{-2+8}{2} ,\frac{1+9}{2} )$

Centre (h, k) = (3 , 5)

The distance of two end points

PQ = $\sqrt{(x_{2}-x_{1} )^{2} +(y_{2} -y_{1} )^{2} }$

$PQ= \sqrt{(8+2 )^{2} +(8 )^{2} }$

PQ = √164 = 12.8

Diameter d = 2r

radius r = d/2

Radius r = 6.4

<u><em>Final answer:-</em></u>

Equation of the circle

(x-h)²+(y-k)² = r²

(x-3)²+(y-5)²=(6.4)²

x² -6x +9 +y² -10y +25 = 40.96

x² -6x +y² -10y = 40.96-34

x² -6x +y² -10y -7= 0

4 0

3 years ago