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Inessa [10]
3 years ago
6

How many ten-digit numbers have at least two equal digits? Please explain!

Mathematics
1 answer:
AveGali [126]3 years ago
7 0

Between 1,000,000,000 and 9,999,999,999 there are 9,000,000,000 different ten-digit numbers. Of those, 9*9! (9 times 9 factorial) = 3,265,920 have all ten digits different, i.e., no two equal digits. Take the difference of those two numbers, and you will have your answer.

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<em>Hope this helps!</em>

<u>Brainliest would be great!</u>

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<u><em>With all care,</em></u>

<u><em>07x12!</em></u>

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Yuto has a bag containing 3 red marbles 5 blue marbles 2 green marbles and 8 yellow Marbles what is the total number of possible
sleet_krkn [62]

Answer:

17

Step-by-step explanation:

Mission Information :

This question is incomplete this line is missing in the question " Rin reaches into the bag, pulls out a blue marble, and puts it in her pocket. Then Misaki reaches in and pulls out a marble. What is the total number of possible outcomes for Misaki’s marble"

Now coming to the solution ,

Given :

Red marbles=3

blue marbles=5

green marbles=2

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Total number of outcomes can be determined by

=Red marbles + blue marbles + green marbles + yellow Marbles

= 3\ +\  5+2 +8=18

As mention in the given question the Rin is pulling the 1 marble ,Now Total number of outcomes

=18-1\\=17

Therefore 17 is the correct answer

6 0
4 years ago
eleven times one number is 9 more than 8 times another number. the first number minus four is half the second number. find the n
andreev551 [17]

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3 years ago
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Sever21 [200]

Answer:

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Simplify: -10 - 90x + 6x - 60
antoniya [11.8K]

<u><em>Answer:</em></u>

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<em><u>Step-by-step explanation:</u></em>

We want to combine like terms:

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Then (-90x) and (+ 6x):

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